Hi! I'm happy to help!
Our total line is JL (4x), and it is split into two parts: JK, and KL. We have our values, and we know that JK+KL=JL, so we can substitute our values and solve for x:
4x=(2x+3)+(x)
4x=3x+3
To solve for x, we have to isolate it on one side of the equation.
First, let's subtract 3x from both sides so that we can isolate x:
4x=3x+3
-3x -3x
x=3
<u>So, our x=3, which means that KL=3.</u>
I hope this was helpful, keep learning! :D
wait what is it i needddd helllpppp
Angles are the space between intersecting lines, and they are measured in degrees or radians
The measure of angle ABC is y + x
<h3>How to determine angle ABC</h3>
The given parameters are:
ABD=y,
DBC=x,
EFH=y,
EFG=x
PQS = SQR = x
To determine the measure of angle ABC, we make use of angle ABD and angle DBC
Note that angle ABD and angle DBC have common vertices at points B and D
So, we have:
ABC = ABD + DBC
Substitute known values
ABC = y + x
Hence, the measure of angle ABC is y + x
Read more about angle measures at:
brainly.com/question/17972372
Answer:
a = - 5
Step-by-step explanation:
Given
0.5(14a + 46) = - 11a - 42 + 5a ← distribute left side
7a + 23 = - 6a - 42 ( add 6a to both sides )
13a + 23 = - 42 ( subtract 23 from both sides )
13a = - 65 ( divide both sides by 13 )
a = - 5
