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3 years ago

If ABC is congruent to DBC the BC bisects the angle ACD

Mathematics

2 answers:

nlexa [21]3 years ago

4 0

Answer: True

Step-by-step explanation: (True) It was right for Apex

tatyana61 [14]3 years ago

3 0

Answer:

True.

If Δ ABC ≅ Δ DBC then BC bisects the angle ∠ ACD.

Step-by-step explanation:

Δ ABC ≅ Δ DBC

∠ ACB ≅ ∠ DCB {corresponding angles of congruent triangles}or(c.p.c.t)

i.e BC is the bisector of ∠ ACD

Hence, TRUE

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Find the answer to the nearest tenth.

Fed [463]

Area=1/2bh h=altitude b=legnth of base b is 3 times h b=3h divide by 3 b/3=h area=1/2bh subsitute b/3 for h 54=1/2(b)(b/3) multiply bothsides by 2/1 108=b(b/3) 108=(b^2)/3 multipy both sides by 3 324=b^2 square root boh sides 18=b legnth of base=18

7 0

3 years ago

In △ABC, point D∈ AB with AD:DB=5:3, point E∈ BC so that BE:EC=1:4. If AABC=40 in2, find AADC, ABDC, and ACDE.

DIA [1.3K]

Answer: Using the proportions between the segments, the area of the triangles are:

1. Area of triangle ADC is 25 in^2.

2. Area of triangle BDC is 15 in^2.

3. Area of triangle CDE is 12 in^2.

Please, see the attached files.

Thanks.

8 0

3 years ago

Hello, I asked help for this problem several times to no answer. I dont understand it and can use any help. Please, and thank yo

Oduvanchick [21]

Check the picture below.

let's recall that a straight-line has 180°, and that sum of all interior angles in a triangle is also 180°.

3 0

3 years ago

10 cm

kirza4 [7]

Um can we see the cylinder

7 0

3 years ago

Simplify by combining like terms 4s + 1/6s + 2 3/5s

HACTEHA [7]

<h3>The solution by combining like terms is 6.7667</h3>

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

$4s + \frac{1}{6}s + 2\frac{3}{5}s$

We have to simplify by combining the like terms

From given,

$4s + \frac{1}{6}s + 2\frac{3}{5}s$

Convert the mixed fraction to improper fraction

$4s + \frac{1}{6}s + \frac{13}{5}s$

Make the denominator same

$\frac{4s \times 30 }{30} + \frac{1s \times 5}{6 \times 5} + \frac{13s \times 6}{5 \times 6}\\\\\frac{120s}{30} + \frac{5s}{30} + \frac{78s}{30}\\\\\frac{203}{30} = 6.7667$

Thus the solution is 6.7667

7 0

3 years ago