Ou should not increase to more than 12 miles next week<span>; ... </span>25 miles<span> a </span>week<span>, usually a 7 </span>milerun<span> ... before I </span>run<span> a half. Using that method</span>
Answer:
4
Step-by-step explanation:
T(n) = n² + 3
T(1) = 1² + 3 = 1 + 3 = 4
Answer:
Step-by-step explanation:
When the coefficients don't lend themselves to solution by substitution or elimination, then Cramer's Rule can be useful. It tells you the solutions to
are ...
- ∆ = bd -ea
- x = (bf -ec)/∆
- y = (cd -fa)/∆
Using that rule here, we find ...
∆ = 5·3 -6·2 = 3
a = (5·54 -6·41)/3 = 5·18 -2·41 = 90 -82 = 8
s = (41·3 -54·2)/3 = 41 -18·2 = 5
This math can be performed in your head, which is the intent of formulating the rule in this way.
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Similarly, if you expect the solutions to be small integers (as here), then graphing is another viable solution method.
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<em>Comment on the question</em>
We're sad to see than only 16 tickets were sold to the two performances by the symphonic band.
Answer:
- The numbers are 8 and 10.
Step-by-step explanation:
Let the numbers be x and y.
The sum of two numbers is eighteen:
The total of three times the smaller and twice the larger is forty-four:
Solve the system by substitution:
Substitute x and solve for y:
- 3(18 - y) + 2y = 44
- 54- 3y + 2y = 44
- 54 - y = 44
- y = 54 - 44
- y = 10
Find x:
So thi sis really simple since you have an equal sign so
(n/3)-(5n/6)=1/3
to subtract fractions, make the bottom number the same
n/3 times 2/2=2n/6
(2n/6)-(5n/6) or (2n-5n)/6 so
-3n/6=1/3
multiply both sides by 6
-3n=6/3=2
-3n=2
divide both sides by 3
-n=2/3
mmultiply boht by -1
n=-2/3
tada
n=-2/3