Answer:
no Solution
Step-by-step explanation:
-12x-12y=4\\ 3x+3y=0
12x-12y=4
add 12y to both sides
12x-12y+12y=4+12y
divid both sides by -12
\frac{-12x}{-12}=\frac{4}{-12}+\frac{12y}{-12}
simplfy
x=-\frac{1+3y}{3}
\mathrm{Substitute\:}x=-\frac{1+3y}{3}
\begin{bmatrix}3\left(-\frac{1+3y}{3}\right)+3y=0\end{bmatrix}
\begin{bmatrix}-1=0\end{bmatrix}
47.12
I did this last year :))
Answer:
86.2%
Step-by-step explanation:
25/29=0.862
Answer:
Step-by-step explanation:
<u>The line x = 3 is parallel to y- axis, the perpendicular line is going to be parallel to x- axis and will have an equation:</u>
<u>Since it passes through the point (-2, 5), it will have a = 5:</u>
- y = 5 is the line we need
