Here are a couple I found:
<u>Similarities</u>:
- They have the same y-intercept of (0,5).
- They are both in slope-intercept form.
<u>Differences</u>:
- The line of y = -13x + 5 "falls" from left to right. The line of y = 2x + 5 "rises" from left to right.
- They have different x-intercepts. (y = 2x + 5 intersects (-
, 0) while y = -13x + 5 intersects at (
, 0)
<u></u>
<u>Explanation</u>:
Slope-intercept form is y = mx + b, and by looking at the equations, they both already fit that format, with m as their slope and b as their y-intercept. Also, since they both have a 5 as that "b," their y-intercepts are the same: (0,5).
As for differences, we can see that the coefficient in place of that "m" is positive in y = <u>2x</u> + 5 and negative in y = <u>-13x</u> + 5. Therefore, one line would rise due to their slope being positive and one would fall due to their slope being negative. They also have two different x-intercepts, which we can calculate by substituting 0 in place of the y, then isolating x.
Answer:
1 Tenths = 10 Hundredths
10.74 - 10.60 = 0.14
0.14 = 14 hundredths
Thus, you need 10 ones, 6 tenths and 14 hundredths to make 10.74.
Answer:
Step-by-step explanation:
a
Answer:
Step-by-step explanation:
For this case we can use the formula for the future value with compound interest given by:
(1)
For this case since the interest is compounded quarterly we have 3 periods each year, since we have 3 quarters in a year.
r represent the rate =0.026
t = 6 represent the number of years
P = 3200 represent the amount invested at the begin
If we apply the formula (1) we got:
So then the balance after 6 years would be approximately 50995 with the conditions provided.
Brayden has 38 bags.
After giving away 15 bags of marbles, Brayden is left with 23 bags.
To find out how many bags he has we do 342 divided by 9 which is 38.
To find out how many marbles are in 15 bags we do 15 x 9 which is 135.
We then do 342 - 135 to find out how many marbles he has left which is 207 and divide 207 by 9 to convert that into bags, which is 23.
