3/5x + 1/3 < 4/5x

The isosceles trapezoid is part of an isosceles triangle with a 34 degree vertex angle. What is the measure of an acute base ang

Sonja [21]

For the answer to the question above asking what is the measure of an acute base angle of the trapezoid?
n acute base angle of the trapezoid would be the same as the triangle.

subtract 34º from 180º, then divide by 2. 

(180 - 34)/2 = 73º
I hope my answer helped you.

4 0

3 years ago

(1 point) (a) Find the point Q that is a distance 0.1 from the point P=(6,6) in the direction of v=⟨−1,1⟩. Give five decimal pla

natima [27]

Answer:

following are the solution to the given points:

Step-by-step explanation:

In point a:

$\vec{v} = -\vec{1 i} +\vec{1j}\\\\|\vec{v}| = \sqrt{-1^2+1^2}$

$=\sqrt{1+1}\\\\=\sqrt{2}$

calculating unit vector:

$\frac{\vec{v}}{|\vec{v}|} = \frac{-1i+1j}{\sqrt{2}}$

the point Q is at a distance h from P(6,6) Here, h=0.1

$a=-6+O.1 \times \frac{-1}{\sqrt{2}}\\\\= 5.92928 \\\\b= 6+O.1 \times \frac{-1}{\sqrt{2}} \\\\= 6.07071$

the value of Q= (5.92928 ,6.07071 )

In point b:

Calculating the directional derivative of $f (x, y) = \sqrt{x+3y}$ at P in the direction of $\vec{v}$

$f_{PQ} (P) =\fracx{f(Q)-f(P)}{h}\\\\$

$=\frac{f(5.92928 ,6.07071)-f(6,6)}{0.1}\\\\=\frac{\sqrt{(5.92928+ 3 \times 6.07071)}-\sqrt{(6+ 3\times 6)}}{0.1}\\\\= \frac{0.197651557}{0.1}\\\\= 1.97651557$

$\vec{v} = 1.97651557$

In point C:

Computing the directional derivative using the partial derivatives of f.

$f_x(x,y)= \frac{1}{2 \sqrt{x+3y}}\\\\ f_x (6,6)= \frac{1}{2 \sqrt{22}}\\\\f_x(x,y)= \frac{1}{\sqrt{x+3y}}\\\\ f_x (6,6)= \frac{1}{\sqrt{22}}\\\\f_{(PQ)}(P)= (f_x \vec{i} + f_y \vec{j}) \cdot \frac{\vec{v}}{|\vec{v}|}\\\\= (\frac{1}{2 \sqrt{22}}\vec{i} + \frac{1}{\sqrt{22}} \vec{j}) \cdot \frac{-1}{\sqrt{2}}\vec{i} + \frac{1}{\sqrt{2}} \vec{j}$

4 0

3 years ago

If Breanna drives a constant speed for 3 hours and travels 180 miles, what is her speed a mile per hour

Georgia [21]

Answer:

60 mph

Step-by-step explanation:

You divide 180 by 3 to get 60 mph

3 0

3 years ago

Soooo this is hard... help?

enot [183]

I just did this test the answer is B :-)

5 0

3 years ago

Read 2 more answers

Now we are testing to see whether taking a vitamin supplement each day has significant health benefits. There are no (known) har

ZanzabumX [31]

Answer:

Concluding that people should take vitamin supplement each day when they don't help.

Step-by-step explanation:

We are given the following in the question:

Hypothesis:

Taking a vitamin supplement each day has significant health benefits and does not have any harmful side effects.

Null hypothesis:

Taking a vitamin supplement each day does not have have significant health benefits.

Alternate hypothesis:

Taking a vitamin supplement each day have have significant health benefits.

Type I error:

It the error of rejecting the a true null hypothesis.

So error I for this situation would be concluding that people should take vitamin supplement each day when they don't help.

3 0

3 years ago

3/5x + 1/3 < 4/5x - 1/3