Answer:
14
Step-by-step explanation:
Simplify the following:
5 - 2×9 + 9^2/3
Hint: | Evaluate 9^2.
9^2 = 81:
5 - 2×9 + 81/3
Hint: | Reduce 81/3 to lowest terms. Start by finding the GCD of 81 and 3.
The gcd of 81 and 3 is 3, so 81/3 = (3×27)/(3×1) = 3/3×27 = 27:
5 - 2×9 + 27
Hint: | Multiply -2 and 9 together.
-2×9 = -18:
5 + -18 + 27
Hint: | Evaluate 5 + 27 using long addition.
| 1 |
| 2 | 7
+ | | 5
| 3 | 2:
32 - 18
Hint: | Subtract 18 from 32.
| 2 | 12
| 3 | 2
- | 1 | 8
| 1 | 4:
Answer: 14
You need to prove that <A = <E
since c is the midpoint of line AE then AC = EC
i dont remember the name of the theroem that states that when a triangle has two sides and an angle in common that it is congruent i think it called SAS congruence therom. use that to prove that the <| s are congruent then use CPCTC to prove that <A = <E. then prove that they are || by usint the int angle therom.
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