Using the intersecting chord theorem:
15 x 2 = 5 x n
Simplify:
30 = 5n
Divide both sides by 5:
n = 30/5
n = 6 m
8 x n+8 = 16 x n+2
Simplify:
8n +64 = 16n +32
Subtract 8n from both sides:
64 = 8n +32
Subtract 32 from both sides:
32 = 8n
Divide both sides by 8:
n = 32 /8
n = 4
Answer:
6y - 13
Step-by-step explanation:
5 - 3(6 - 2y)
Distribute;
5 - 18 + 6y
-13 + 6y <em>OR</em> 6y - 13
Remember, parenthaees are like < and > and brackets ar like ≤ and ≥
domain is how far the x values go
x is left to right
we see they go from -3 to 5, with a filled in dot at -3 and empty dot at 5
means include -3 but not including 5
so like -3≤x<5
or in interval notation
[-3,5) is the domain
range
highest to lowest y value
range is from y=3 to y=-1
we gots full dots so we use brackets
range is [-1,3]
Domain=[-3,5)
Range=[-1,3]
B. read above and understand it
The answer is: " 2 :5 " ; or, write as: " 2/5 " .
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The ratio of 'girls' to 'all students' is: "2: 5 " ; or, write as: " 2/5 ".
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Explanation:
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Given: The ratio of boys to girls is: " 3:2 " .
Problem: Find the ratio of "girls" to "all students:
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Note: This ratio of "boys to girls", which is " 3 : 2 " ;
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→ can be expressed as " 3x: 2x" ;
in which the total number of students is: " 3x + 2x " = 5x " .
→ The total number of students is represented as: " 5x " .
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→ The ratio of "girls to boys" is: "2x : 3x" .
→ {that is; the "inverse" of the ratio of "boys to girls"} ;
→ {that is; the "inverse" of " 3x: 2x" } ; → which is: " 2x : 3x " .
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The ratio of "girls" to "all students" is: "2x : 5x " ; or " 2x/5x " ;
→ Both "x" values cancel ; {since: " x/x = 1 "} ;
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→ and we have the answer: " 2 :5 " ; or, write as: " 2/5 " .
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The ratio of 'girls' to 'all students' is: " 2 :5 " ; or, write as: " 2/5 ".
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Dilation because the sides will not be the same size as the original
