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Nady [450]
3 years ago
7

A heat engine is designed to do work. This is possible only if certain relationships between the heats and temperatures at the i

nput and output hold true. Which of the following sets of statements must apply for the heat engine to do work?A) Qh < Qc and Th < TcB) Qh > Qc and Th < TcC) Qh < Qc and Th > TcD) Qh > Qc and Th > Tc
Physics
1 answer:
ryzh [129]3 years ago
5 0

Answer: option D

Explanation: let us first define an heat engine.

An heat engine is that device that converts partly heat energy into mechanical energy.

Inside the heat engine is a substance that undergoes compression and expansion, intake and outtake of heat, this is known as a working substance.

For heat engines to work perfectly, the working substance has to take a substantial large amount of heat energy from a source, this source is the hot reservoir, the amount of heat energy given out by this reservoir is Qh and the temperature at this region is Th. The heat from the hot reservoir is accepted by the working substances and sent to a region that will discard it out, this region is known as the cold reservoir and the heat energy at this point is Qc and temperature is Tc.

Judging by the direction of heat flow, heat energy moves from hot reservoir to the cold reservoir for the heat engine to work perfectly fine, hence Qh must be greater than Qc and Th must be greater than Tc.

Hence Qh>Qc and Th>Tc

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A converging lens of focal length 20 cm is placed in contact with, and to the left of, a diverging lens of focal length 30 cm. I
scZoUnD [109]

Answer:

Magnification will be equal to 3

Explanation:

We have given focal length of the converging lens F_1=20cm

Focal length of the diverging lens F_2=30cm

Object is placed 40 cm to the length of the converging lens d = 40 cm

Combination of the focal length will be equal to

\frac{1}{F}=\frac{1}{F_1}+\frac{1}{F_2}

\frac{1}{F}=\frac{1}{20}+\frac{1}{-30}=\frac{1}{20}-\frac{1}{30}=\frac{1}{60}

F = 60 cm

So combination of the focal length will be 60 cm

Magnification is given by

M=\frac{F}{F-d}=\frac{60}{60-40}=3

So magnification will be equal to 3

3 0
3 years ago
Vector A → has magnitude 8.78 m at 37.0 ∘ from the + x axis. Vector B → has magnitude 8.26 m at 135.0 ∘ from the + x axis. Vecto
kodGreya [7K]

Answer:

R = (- 3.72î + 8.29j)

Magnitude of R = 9.09 m

Explanation:

Let î and j represent unit vectors along the x and y axis respectively.

Vector A --> magnitude 8.78 m, direction 37.0° from the +x-axis

Let the x and y components of this vector be Aₓ and Aᵧ

A = (Aₓî + Aᵧj) m

The components given magnitude and direction from the +x-axis are calculated as

Aₓ = A cos θ and Aᵧ = A sin θ

Aₓ = (8.78 cos 37°) = 7.01 m

Aᵧ = (8.78 sin 37°) = 5.28 m

A = (7.01î + 5.28j) m

Vector B has magnitude 8.26 m and direction 135° from the +x-axis

B = (Bₓî + Bᵧj) m

Bₓ = (8.26 cos 135°) = - 5.84 m

Bᵧ = (8.26 sin 135°) = 5.84 m

B = (-5.84î + 5.84j) m

Vector C has magnitude 5.65 m and direction 210° from the +x-axis

C = (Cₓî + Cᵧj) m

Cₓ = (5.65 cos 210°) = - 4.89 m

Cᵧ = (5.65 sin 210°) = - 2.83 m

C = (- 4.89î - 2.83j) m

The resultant force is a vector sum of all the forces. Let the resultant force be R

R = (Rₓî + Rᵧj) m

R = A + B + C = (7.01î + 5.28j) + (-5.84î + 5.84j) + (- 4.89î - 2.83j)

Summing the î and j components seperately,

R = (- 3.72î + 8.29j) m

To get its magnitude,

Magnitude of R = √(Rₓ² + Rᵧ²) = √((-3.72)² + (8.29)²) = 9.09 m

8 0
4 years ago
What physical quantity is a measure of the amount of inertia an object has?
satela [25.4K]
Mass is the physical quantity
3 0
4 years ago
A solid cube of side 5cm has a mass of 250g. What is its density in kgm ??​
Mariulka [41]

Answer:

5kgm

Explanation:

convert cm to m and g to kg

250/1000=0.25kg

5/1000=0.05m

then find the density

density=mass/volume

=0.25kg/0.05m

=5kgm

7 0
3 years ago
32. Which type of electromagnetic wave is used for nuclear power and medical treatment?
adelina 88 [10]

Answer:

Answers at the bottom!!

Explanation:

For the first answer: Gamma ray

Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.

For the second answer: They both have technological uses.

In my opinion I'm pretty sure it's A because we do use microwaves and x-rays as technological uses.

Hope this helps!!

Happy Holidays and Season Greeting!!

ii Feliz Navidad a todos !!

3 0
3 years ago
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