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3 years ago

Pls solve for x thank you

Mathematics

2 answers:

Margaret [11]3 years ago

8 0

X=4 make sure to do pemdas!

Helen [10]3 years ago

3 0

Answer:

X=4

Explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

hope this helps! <3

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Rewrite the following in the form log(c)<br> log(6)−log(3)

Genrish500 [490]

<h3>Answer: log(2)</h3>

Explanation:

The rule to use here is log(x)-log(y) = log(x/y)

So,

log(6)-log(3) = log(6/3) = log(2)

6 0

2 years ago

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<img src="https://tex.z-dn.net/?f=24x%5E%7B2%7D%2Bbx%5E%7B2%7D%20%3D25x%5E%7B2%7D" id="TexFormula1" title="24x^{2}+bx^{2} =25x^{

Liula [17]

Answer:

x = 0

Step-by-step explanation:

Subtract 25x^2 from both sides

24x^2 + bx^2 - 25x^2 - 25x^2

Simplify

bx^2 - x^2 = 0

Factor bx^2 - x^2: x^2(b - 1)

bx^2 - x^2

Factor out common term x^2

= x^2 (b - 1)

x^2(b - 1) = 0

Using the Zero Factor Principle: If ab = 0 then a = 0 or b = 0

x^2 = 0

Apply rule x^n = 0 x = 0

x = 0

8 0

3 years ago

a cone with radius of 3 feet and a height of 5 feet is placed on top of a cylinder as shown find the volume of the total figure

Darina [25.2K]

Answer: Volume of the cone = 47.12 cubic feet.

Step-by-step explanation:

You didn't finish the question so Idid the best with what I had, you also didn't include the image that I think was supposed to be included.

To solve for the full volume including the cylinder, use the cylinder's volume formula.

Volume of a cylinder = height (pi) (r^2) and then add it to the 47.12.

Volume of a cone is pi(r^2)(h/3)

plug and chug!

h stands for height and r stands for radius.

5 0

2 years ago

The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of

ycow [4]

The length of the longer base is 41 ft.

<u><em>Explanation</em></u>

Lets assume, length of one base is $x$ ft.

As, another base is 19 less than five times the length of this base, so the length of another base $= (5x- 19) ft.$

The trapezoid has a height of 18 ft and area of 477 ft²

Formula for Area of trapezoid, $A=\frac{1}{2} (a+b)*h$ , where $a, b$ = Two bases of trapezoid and $h$ = height of the trapezoid.

Given in the question: $A= 477$ and $h= 18$

We have also two bases as: $a= x$ and $b= 5x-19$

So, according to the above formula...

$A= \frac{1}{2}(a+b)h\\\\ 477=\frac{1}{2}(x+5x-19)*18\\\\ 477=9(6x-19)\\\\477= 54x-171\\\\477+171=54x\\\\648=54x\\\\x=\frac{648}{54} = 12$

So, length of one base is $12 ft$ and another base $=(5*12-19)ft =(60-19)ft = 41 ft$

That means, the length of the longer base is 41 ft.

8 0

3 years ago

I am confused help me

bonufazy [111]

2x+3=17
subtract 3 from both sides
2x=14
divide both sides by 2 and get
x=7

4 0

3 years ago

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