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2 years ago

This is such an easy question so could you answer it? thanks will give brainliest and a medal:)!

Mathematics

1 answer:

Ugo [173]2 years ago

6 0

The answer is 14 if you add all numbers in the chart 70 and above the answer will be 14

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Find the circumference and the area of a circle with radius 3 m.

Effectus [21]

Answer:

$\boxed {c= 18.84 \ m}$

$\boxed {a=28.26 \ m^2}$

Step-by-step explanation:

We are asked to find the circumference and area of a circle with a radius of 3 meters.

<h3>1. Circumference </h3>

The circumference is the perimeter of a circle. It is calculated using the following formula:

$c= \pi d$

We know the radius of the circle is 3 meters, but we must find the radius. The radius is the line from the center to the circle's edge, while the diameter is the line through the center from edge to edge. Therefore, the diameter is twice the radius.

d= 2 r
d= 2 * 3 m
d= 6 m

The diameter is 6 meters and we are using 3.14 for pi. Substitute these values into the circumference formula.

$c= (3.14)(6 \ m )$

Multiply.

$\bold {c= 18.84 \ m}$

The area is the size of the circle's surface. It is calculated using the following formula.

$a= \pi r^2$

The radius is 3 meters are we are using 3.14 for pi. Substitute these values into the area formula.

$a= (3.14)(3 \ m)^2$

Solve the exponent.

(3 m)² = (3 m)(3 m)= 9 m²

$a= (3.14)(9 \ m)^2$

$\bold {a=28.26 \ m^2}$

The circumference is 18.84 meters and the area is 28.26 square meters.

6 0

2 years ago

Solve x2 − 12x + 5 = 0 using the completing-the-square method. x = six plus or minus the square root of five x = negative six pl

Andru [333]

we are given

$x^2-12x+5=0$

we have to solve it by completing square method

step-1: Move 5 on right side

$x^2-12x+5-5=0-5$

$x^2-12x=-5$

step-2: Break middle term

$x^2-2*6*x=-5$

step-3: Add 6^2 both sides

$x^2-2*6*x+(6)^2=-5+(6)^2$

$(x-6)^2=31$

step-3: Solve for x

$\sqrt{(x-6)^2} =\sqrt{31}$

we wil get two values

First value is

$x-6=\sqrt{31}$

add both sides 6

$x-6+6=6+\sqrt{31}$

$x=6+\sqrt{31}$

Second value is

$x-6=-\sqrt{31}$

add both sides 6

$x-6+6=6-\sqrt{31}$

$x=6-\sqrt{31}$

so, solutions are

$x=6+\sqrt{31}$

$x=6-\sqrt{31}$ .............Answer

5 0

2 years ago

Math 8: Linear Functions, Part 2

Studentka2010 [4]

Answer:

$\boxed{\text{1. y + 5 = -4(x - 3); \qquad 2. y - 8 = x + 1}}$

Step-by-step explanation:

Question 1

The point-slope formula for a straight line is

y – y₁ = m(x – x₁)

x₁ = 3; y₁ = -5; m = -4

Substitute the values

$\boxed{\textbf{y + 5 = -4(x - 3)}}$

The diagram shows the graph of equation 1 (red) with slope -4 passing through (3,-5).

Question 2

x₁ = -1; y₁ = 8; m = 1

Substitute the values

$\boxed{\textbf{y - 8 = x + 1}}$

The diagram shows the graph of equation 2 (green) with slope 1 passing through (-1,8).

3 0

3 years ago

30 ounce box of cerebral contains 12 servings

gulaghasi [49]

Answer:

okay?

Step-by-step explanation:

is that supposed to be like is that true or false or am I just not understanding if that's a question or not

8 0

2 years ago

Read 2 more answers

A rectangular vegetable garden will have a width that is feet less than the length, and an area of square feet. If x represents

ivanzaharov [21]

8(8-2)=48
8(6)=48
therefore x=8

5 0

1 year ago