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Rina8888 [55]
3 years ago
5

X=3-√5 find the value of √x+ 1/√x

Mathematics
1 answer:
Rama09 [41]3 years ago
5 0

\bf x = 3-\sqrt{5} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{x}+\cfrac{1}{\sqrt{x}}\implies (3-\sqrt{5})+\cfrac{1}{3-\sqrt{5}}\qquad \impliedby \textit{let use the LCD of }3-\sqrt{5} \\\\\\ \cfrac{(3-\sqrt{5})3-(3-\sqrt{5})\sqrt{5}+(1)1}{3-\sqrt{5}} \implies \cfrac{9-3\sqrt{5}-(3\sqrt{5}-5)+1}{3-\sqrt{5}} \\\\\\ \cfrac{9-3\sqrt{5}-3\sqrt{5}+5+1}{3-\sqrt{5}}\implies \cfrac{15-6\sqrt{5}}{3-\sqrt{5}}

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A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 48.0 and 58.
Yanka [14]

Answer: 0.025

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].

The probability density function :-

f(x)=\dfrac{1}{58-48}=\dfrac{1}{10}

Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-

\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025

Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025

Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025

5 0
3 years ago
16, 4,1,...<br> Find the 6th term
Vlada [557]

Let's see what to do...

_________________________________

Step (1)

Look : 16 , 10 , 4 , ...

It is an arithmetic sequence.

So first we have to find the value of the ratio(( d )) .

To do this, we need to subtract each sentence minus the previous sentence.

So we have : 10 - 16 = - 6

_________________________________

Step (2)

To find the nth sentence in an arithmetic sequence, we must use the following equation :

t(n) = t(1) + (n - 1)d

_________________________________

Step (3)

To find the 6th term just need to put the following parameters in the above sequence.

t(1) = 16 ------ n = 6 ------ d = -6

t(6) = 16 + (6 - 1)( - 6)

t(6) = 16 + (5)( - 6)

t(6) = 16 + ( - 30)

t(6) = 16 - 30

t(6) =  - 14

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0
3 years ago
M + 20 = 11m - 6<br><br> can somebody show me how to solve this?
elena55 [62]
This ends up being:

-10m = -26

M= 2.6

Basically you’re doing basic algebra. You take the “11m” and subtract it to the positive (1) m. And you basically should see 1m-11m EQUALING -10m. Don’t let the negatives confuse you.

Then you take the 20 and subtract it to -6. It should look like: -6-20 = -26.

Then divide-10 to -26, then you should get 2.6. And yes positive!!

Hope this helped!

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The answer is on Chegg.com

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