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Rina8888 [55]
4 years ago
5

X=3-√5 find the value of √x+ 1/√x

Mathematics
1 answer:
Rama09 [41]4 years ago
5 0

\bf x = 3-\sqrt{5} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{x}+\cfrac{1}{\sqrt{x}}\implies (3-\sqrt{5})+\cfrac{1}{3-\sqrt{5}}\qquad \impliedby \textit{let use the LCD of }3-\sqrt{5} \\\\\\ \cfrac{(3-\sqrt{5})3-(3-\sqrt{5})\sqrt{5}+(1)1}{3-\sqrt{5}} \implies \cfrac{9-3\sqrt{5}-(3\sqrt{5}-5)+1}{3-\sqrt{5}} \\\\\\ \cfrac{9-3\sqrt{5}-3\sqrt{5}+5+1}{3-\sqrt{5}}\implies \cfrac{15-6\sqrt{5}}{3-\sqrt{5}}

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Answer:

A) -4

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C) no values of x

Step-by-step explanation:

1) slope of m: (3-2)/(10-8) = ½

m(x) = ½x + c

2 = ½(8) + c

c = -2

m(x) = ½x - 2

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B) y-intercept of:

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from the equation found before

2 - (-2) = 4 units apart

C) m(x) = (x-4)/2

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3 years ago
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den301095 [7]

Answer:

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Step-by-step explanation:

we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e

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therefore,

\displaystyle \rm A _{square } = A _{rect}

recall the formula of the area of square and rectangle so,

\displaystyle  {s}^{2} = lw

now assign variables

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thus substitute:

\displaystyle 32cmx =  {16cm}^{2}

simplify square:

\displaystyle 32cmx = 256cm^2

divide both sides by 32:

\displaystyle  \boxed{x = 8cm}

and we're done!

3 0
3 years ago
Read 2 more answers
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