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Alexus [3.1K]
3 years ago
10

Resolva os seguintes exercícios sobre os Números racionais, a partir de situações problema: Para encher um álbum de figurinhas,

Karina contribuiu com 1/6 das figurinhas, enquanto Cristina contribuiu com 3/4 das figurinhas. Com que fração das figurinhas as duas juntas contribuíram?
Mathematics
1 answer:
Vesna [10]3 years ago
7 0

Answer:

11/12

Step-by-step explanation:

Nesta questão, estamos interessados ​​em saber em que fração do álbum de figurinhas ambos contribuíram.

Pela pergunta, ficamos sabendo que Karina contribuiu com 1/6 enquanto Cristina contribuiu com 3/4.

Portanto, para encontrar a fração com a qual ambos contribuem, simplesmente adicionamos as duas frações.

Matematicamente, isso seria 1/6 + 3/4 = (2 + 9) / 12 = 11/12

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What values of b satisfy 4(3b + 2)2 = 64?
Vikentia [17]
Given the equation 4(3b + 2)² = 64, dividing both sides of the equation by 4, we have (3b + 2)² = 16 and getting the square root of both sides, (3b + 2) = 4 and (3b + 2) = -4 We can solve for b for each equation and have 3b = 2 | 3b = -6 b = 2/3 | b = -2 Therefore, the values of b are 2/3 and -2 and from the choices, the answer is <span>A: b = 2/3 and b = -2.</span>
8 0
2 years ago
What is the base five representation of The number 219
ICE Princess25 [194]

assuming 219_{10}

Then the column values for base five here are

5³  5²  5^{1}  5^{0}

We can get 1 × 5³ = 125 → 219 - 125 = 94

We can get 3 × 5² = 75 → 94 - 75 = 19

We can get 3 x 5^{1} → 19 - 15 = 4

and 4 = 4 × 5^{0}

Thus 219_{10} = 1334_{5}

As a check

(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219


3 0
3 years ago
In ΔIJK, k = 57 inches, i = 37 inches and ∠J=141°. Find ∠I, to the nearest degree.
Sonbull [250]

Answer:

<I= 15degrees

Step-by-step explanation:

Using the cosine rule formulae;

j² = i²+k²-2i cos <J

j² = 37²+57² - 2(37)(57)cos <141

j² = 1369+ 3249- 4218cos <141

j² = 4618- 4218cos <141

j² = 4618-(-3,278)

j²= 7,896

j = √7,896

j = 88.86inches

Next is to get <I

i² = j²+k²-2jk cos <I

37² = 88.86²+57² - 2(88.86)(57)cos <I

1369 = 7,896.0996+ 3249- 10,130.04cos <I

1369 = 11,145.0996 - 10,130.04cos <I

1369 - 11,145.0996 = - 10,130.04cos <I

-9,776.0996=- 10,130.04cos <I

cos <I =9,776.0996 /10,130.04

cos<I = 0.96506

<I = 15.19

<I= 15degrees

8 0
2 years ago
8% of 44 show work please and an answer ciz i domt understand
nalin [4]
Hey there! 

These are the steps involved in answering the question:

Change 8% into a decimal. To do this, just move the decimal place, 2 places to the left.
You get 0.8

Now, multiply 0.8 by 44. 
0.8 x 44 = 35.2

So, the final answer is: 35.2.

<span>(If you feel that my answer has helped you, please consider rating it and giving it a thank you! Also, feel free to choose the best answer, the brainliest answer!)
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<span>Thank you for being part of the brainly community! :D</span>
7 0
3 years ago
A mattress store sells only king, queen and twin-size mattresses. Sales records at the store indicate that the number of queen-s
Nitella [24]

Answer:

The probability that the next mattress sold is either king or queen-size is P=0.8.

Step-by-step explanation:

We have 3 types of matress: queen size (Q), king size (K) and twin size (T).

We will treat the probability as the proportion (or relative frequency) of sales of each type of matress.

We know that the number of queen-size mattresses sold is one-fourth the number of king and twin-size mattresses combined. This can be expressed as:

P_Q=\dfrac{P_K+P_T}{4}\\\\\\4P_Q-P_K-P_T=0

We also know that three times as many king-size mattresses are sold as twin-size mattresses. We can express that as:

P_K=3P_T\\\\P_K-3P_T=0

Finally, we know that the sum of probablities has to be 1, or 100%.

P_Q+P_K+P_T=1

We can solve this by sustitution:

P_K=3P_T\\\\4P_Q=P_K+P_T=3P_T+P_T=4P_T\\\\P_Q=P_T\\\\\\P_Q+P_K+P_T=1\\\\P_T+3P_T+P_T=1\\\\5P_T=1\\\\P_T=0.2\\\\\\P_Q=P_T=0.2\\\\P_K=3P_T=3\cdot0.2=0.6

Now we know the probabilities of each of the matress types.

The probability that the next matress sold is either king or queen-size is:

P_K+P_Q=0.6+0.2=0.8

8 0
3 years ago
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