Since ![[0,4]=[0,1]\cup(1,4]](https://tex.z-dn.net/?f=%5B0%2C4%5D%3D%5B0%2C1%5D%5Ccup%281%2C4%5D)
, we can rewrite the integral as
Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:
Both integrals are quite immediate: you only need to use the power rule
to get
![\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E11-3t%5E2%5C%3Bdt%20%3D%20%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%2C%5Cquad%20%5Cint_1%5E4%202t%5C%3B%20dt%20%3D%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4)
Now we only need to evaluate the antiderivatives:
![\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15](https://tex.z-dn.net/?f=%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%20%3D%201-1%5E3%3D0%2C%5Cquad%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4%20%3D%204%5E2-1%5E2%3D15)
So, the final answer is 15.
6c^2 - c + 1 + 4c - 2c^2 - 8c
= 4c^2 - 5c + 1
= (4c - 1)(c - 1)
Answer:
Yes
Step-by-step explanation:
8²+6²=100
√100
=10
<span>You are given the word alabama and you are asked to find how many distinguishable 7 letter "words" can be formed from it.
ALABAMA has seven letters so we will start at 7!
Counting the number of A's in the word we have 4 A's and so we will divide it by 4!
</span>Counting the number of L's in the word we have 1 L and so we will divide it by 1!
Counting the number of B's in the word we have 1 B and so we will divide it by 1!
Counting the number of M's in the word we have 1 M and so we will divide it by 1!
And so the number of ways is 7! / (4! x 1! x 1! x 1!) = 210 words.
