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3241004551 [841]
3 years ago
8

If the dimensions of a rectangle are A plus 3b and A minus 3b what is the area of the rectangle

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

area=legnth times width

we notice this is a special case

(a+b)(a-b)=a^2-b^2

area=(a+3b)(a-3b)=a^2-9b^2

area=a^2-9b^2

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Annie earns $7.50 per hour working after school. She needs at least $185 for a stereo system. Write an inequality that describes
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How many terms are in (3x^2-3)(3x^2+3)
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The number of terms in the expression given is; 2.

<h3>How many term are in the expression given?</h3>

It follows from the task content that the expression given is; (3x^2-3)(3x^2+3).

It therefore follows the converse of law regarding difference of two squares that the expression given can be rewritten as;

= 9x⁴ -9

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2 years ago
Which expression is equivalent to 3(5+4)
guajiro [1.7K]

Answer:

3(15+12)

Step-by-step explanation:

3(5+4)

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2 years ago
Please help me out............................
Alina [70]

Answer:

<h2>b = 15°</h2>

Step-by-step explanation:

If Pq = RQ then ΔPQR is the isosceles triangle. The angles QPR and PRQ have the same measures.

We know: The sum of the measures of the angeles in the triangle is equal 180°. Therefore we have the equation:

m∠QPR + m∠PRQ + m∠RQP = 180°

We have

m∠QPR = m∠PRQ and m∠RQP = 60°

Therefore

2(m∠QPR) + 60° = 180°       <em>subtract 60° from both sides</em>

2(m∠QPR) = 120°           <em>divide both sides by 2</em>

m∠QPR = 60° and m∠PRQ = 60°

Therefore ΔPRQ is equaliteral.

ΔPSR is isosceles. Therefore ∠SPR and ∠PRS are congruent. Therefore

m∠SPR = m∠PRS

In ΔAPS we have:

m∠SPR + m∠PRS + m∠RSP = 180°

2(m∠SPR) + 90° = 180°            <em>subtract 90° from both sides</em>

2(m∠SPR) = 90°             <em>divide both sides by 2</em>

m∠SPR = 45° and m∠PRS = 45°

m∠PRQ = m∠PRS + b

Susbtitute:

60° = 45° + b           <em>subtract 45° from both sides</em>

15° = b

3 0
3 years ago
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