3 years ago

If the dimensions of a rectangle are A plus 3b and A minus 3b what is the area of the rectangle

Mathematics

1 answer:

tresset_1 [31]3 years ago

5 0

area=legnth times width

we notice this is a special case

(a+b)(a-b)=a^2-b^2

area=(a+3b)(a-3b)=a^2-9b^2

area=a^2-9b^2

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What is the sum? 3 y / Y 2 + 7 y + 10 + 2 / y + 2

kap26 [50]

Answer:

5/(y+5)

Step-by-step explanation:

Perhaps you want the sum ...

$\dfrac{3y}{y^2+7y+10}+\dfrac{2}{y+2}\\\\=\dfrac{3y}{(y+2)(y+5)}+\dfrac{2(y+5)}{(y+2)(y+5)}=\dfrac{3y+2(y+5)}{(y+2)(y+5)}\\\\=\dfrac{5y+10}{(y+2)(y+5)}=\dfrac{5(y+2)}{(y+2)(y+5)}=\boxed{\dfrac{5}{y+5}}$

_____

<em>Comment on rational expressions</em>

When writing ratios in plain text, it is imperative to put parentheses around numerators and denominators. (If the numerator is a product only, then parentheses are optional.)

Your expression might be properly written as ...

3y/(y^2 +7y +10) +2/(y+2)

As you have written it, it simplifies to ...

3(y/y)2 +7y +10 +2/y +2 = 3·2 +7y +2/y +12

= 7y +2/y +18

Please note, too, the exponentiation symbol (^).

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3 years ago

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fredd [130]

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