(6c^2-c+1)-(-4c+2c^2+8c)

Mathematics

1 answer:

Natalka [10]3 years ago

3 0

6c^2 - c + 1 + 4c - 2c^2 - 8c
= 4c^2 - 5c + 1
= (4c - 1)(c - 1)

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$\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
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cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
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