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nasty-shy [4]
3 years ago
13

A^3b^2 divided by a^-1b^-3

Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

\frac{a^3 b^2}{\frac{1}{a} \frac{1}{b^3}}

And simplifying we got:

a^3 b^2 a b^3

a^3 a b^2 b^3 = a^{3+1} b^{2+3} = a^4 b^5

Step-by-step explanation:

We want to simplify the following expression:

\frac{a^3 b^2}{a^{-1} b^{-3}}

And we can rewrite this expression using this property for any number a:

a^{-1}= \frac{1}{a}

And using this property we have:

\frac{a^3 b^2}{\frac{1}{a} \frac{1}{b^3}}

And simplifying we got:

a^3 b^2 a b^3

a^3 a b^2 b^3 = a^{3+1} b^{2+3} = a^4 b^5

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3 years ago
Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab
Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx

If f(x)=x^2, then

f'(x)=2x

and

b=0\\ \\a=2

Therefore,

SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx

Apply substitution

x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du

Then

SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du

Now

\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))

Hence,

SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}

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3 years ago
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UkoKoshka [18]

Answer:

55

Step-by-step explanation:

here's the working out i did

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2 years ago
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Len [333]

Answer:

The answer is 170

Step-by-step explanation:

Because 8 + 9 = 17, if we multiply all of these values by ten or add a zero to the end of each number, we should get

80 + 90 = 170

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2 years ago
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