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3 years ago

The length of a rectangle is 13 ft. And its width is 49 ft. What is its perimeter? 512 ft 427 ft 79 ft 159 ft

Mathematics

2 answers:

Evgen [1.6K]3 years ago

8 0

Answer:

its 124?

Step-by-step explanation:

crimeas [40]3 years ago

7 0

Answer:

= 124 ft

Step-by-step explanation:

Perimeter of a rectangle is

P = 2(l+w)

We know the length is 13 and the width is 49

P = 2(13+49)

=2(62)

= 124 ft

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Find the point on the plane 4x+3y+z=10 that is nearest to (2,0,1). What are the values of x, y, and z for the point? x= 28 /

MariettaO [177]

Answer:

$\frac{1}{\sqrt{26}}$ .

Step-by-step explanation:

The minimun distance between a point and a plane is the perpendicular distance. The formula is

d = $\frac{|Ax_0+By_0+Cz_0+D|}{\sqrt{A^{2}+B^{2}+C^{2}}}$

where $(x_0,y_0,z_0)=(2,0,1)$ , A=4, B=3, C=1 and D=-10. So, the distance is

d = $\frac{|8+1-10|}{\sqrt{16+9+1}}$

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Step-by-step explanation:

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3 years ago

Determine whether there is a difference between the two data sets that is not apparent from a comparison of the measures of cent

Iteru [2.4K]

Answer:

It seems the question is incomplete as the two data sets implied from the question are not visible.

However, two data sets having identical measures of center have a difference.

Step-by-step explanation:

Let's consider these two data sets:

2, 2, 3, 5, 6, 6 and 1, 1, 1, 1, 1, 19

Both were contrived.

The most reliable among the measures of center is the mean. The mean of each is calculated by summing the data and dividing by the number of elements. In both sets, the mean is 4.

The data in the first set seem to be concentrated around the mean indeed. But for the second data set, one of them, 19, is obviously very far from the others and the mean. We need another measure to describe this: standard deviation.

Its formula is:

$\rho=\sqrt{\dfrac{\sum (x-\overline{x})^2}{n}}$

$x$ represents each data, $\overline{x}$ is the mean and $n$ is the number of items. $x-\overline{x}$ is the deviation from the mean of each data item.