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Irina-Kira [14]

2 years ago

8

Given that f(x) = x2 – 14x + 45 and g(x) = 2 – 9, find f(x) – g(x) and

1 answer:

seropon [69]2 years ago

8 0

Answer:

x2-14x+52 is the answer in my calculation.

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Find the missing length of the triangle.<br> 10 in.<br> 16<br> 26 in.

Yanka [14]

Answer:

24

Step-by-step explanation:

26x26=676

10x10=100

676/100=576

The square root of 576 is 24.

8 0

2 years ago

emma gave 2/5 of her money and an additional $9 to olivia. she gave 4/7 of her remaining money and an additional $1 to Ava. emma

alexandr1967 [171]

Yo wsp how is it going kane

5 0

2 years ago

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How to graph y = 2|x + 3| - 4

mr_godi [17]

The x-intercepts and the y-intercepts of the function is that determines the graph is:

x-intercepts = (-5,0) and (-1,0)
y-intercepts = (0,2)

<h3>How do we graph the function y = f(x) of an absolute equation?</h3>

The function of an absolute equation can be graphed by determining the values of x-intercepts and the y-intercepts of the function.

From the given equation:

y = 2|x+3| - 4

To determine the y-intercepts, we need to set the values of x to zero, and vice versa for x-intercepts.

By doing so, the x-intercepts and the y-intercepts of the function is:

x-intercepts = (-5,0) and (-1,0)
y-intercepts = (0,2)

Therefore, since we know the x and y-intercepts, the graph of the absolute value can be seen as plotted below.

Learn more about determining the graph of an absolute equation here:

brainly.com/question/2166748

#SPJ1

8 0

1 year ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

Can some one help me set up an equation out of these word problems? PLEASE HELP!!!

Elanso [62]

1: 2/5=emails 3.6hrs=emails, 3.6=2/5 5-2=3 3.6•3=__hours of work

2. 294+83=$__

3. 3•x=hw 64/4=__•3=__hrs on math

4. Idk sorry

Sorry if some of these are wrong but I'm pretty sure there right.

5 0

2 years ago

Read 2 more answers