y=3x+1
Use the slope-intercept form to find the slope and y-intercept
The slope-intercept form is y=mx+b
, where m is the slope and b
is the y-intercept.
y=mx+b
Find the values of m
and b using the form y=mx+b
.
m=3
b=1
The slope of the line is the value of m
, and the y-intercept is the value of b
.
Slope: 3
Y-Intercept: 1
Any line can be graphed using two points. Select two x
values, and plug them into the equation to find the corresponding y
values.
Choose 0
to substitute in for x
to find the ordered pair.
Replace the variable x
with 0
in the expression.
f(0)=3(0)+1
Simplify the result.
Tap for more steps...
1
The first point is (0,1)
.
(0,1)
Choose 1
to substitute in for x
to find the ordered pair.
Tap for fewer steps...
Replace the variable x
with 1
in the expression.
f(1)=3(1)+1
Simplify the result.
Multiply 3
by 1
.
f(1)=3+1
Add 3
and 1
.
f(1)=4
The final answer is 4
.
4
The second point is (1,4)
.
(1,4)
Create a table of the x
and y
values.
xy0114
Graph the line using the slope and the y-intercept, or the points.
Slope: 3
Y-Intercept: 1
xy0114
{2x + 3y = 18
x + 7y = 31}
2x+ 3y = 18
x=31-7
2(31-7)+3y=18
y=4
x=31-7*4
x=3
(x,y) = (3,4)
He planted 92 of those because 12 times 6 is 72 and 72 plus 20 is 92 therefore the answer is 92
Whenever you face the problem that deals with maxima or minima you should keep in mind that minima/maxima of a function is always a point where it's derivative is equal to zero.
To solve your problem we first need to find an equation of net benefits. Net benefits are expressed as a difference between total benefits and total cost. We can denote this function with B(y).
B(y)=b-c
B(y)=100y-18y²
Now that we have a net benefits function we need find it's derivate with respect to y.

Now we must find at which point this function is equal to zero.
0=100-36y
36y=100
y=2.8
Now that we know at which point our function reaches maxima we just plug that number back into our equation for net benefits and we get our answer.
B(2.8)=100(2.8)-18(2.8)²=138.88≈139.
One thing that always helps is to have your function graphed. It will give you a good insight into how your function behaves and allow you to identify minima/maxima points.