Answer: 3.4 h
Explanation:
1) The basis to solve this kind of problems is that the speed of working together is equal to the sum of the individual speeds.
This is: speed of doing the project together = speed of Cody working alone + speed of Kaitlyin working alone.
2) Speed of Cody
Cody can complete the project in 8 hours => 1 project / 8 h
3) Speed of Kaitlyn
Kaitlyn can complete the project in 6 houres => 1 project / 6 h
4) Speed working together:
1 / 8 + 1 / 6 = [6 + 8] / (6*8 = 14 / 48 = 7 / 24
7/24 is the velocity or working together meaning that they can complete 7 projects in 24 hours.
Then, the time to complete the entire project is the inverse: 24 hours / 7 projects ≈ 3.4 hours / project.Meaning 3.4 hours to complete the project.
Answer is 24.
firsty remember OF= MULTIPLY
NOW we can calculate this easily
here the equation is given
2/5×60. u can solve this in given ways below….…..
1……….
u can simply divided 60 by 5. which is equal to 12. and now the equation remain 2×12 . & it's equal to 24. which is our answer.
2……….
u can write 2/5 in decimals by dividing this . so 2/5 is equal to 0.4
and now u r left with 0.4×60
so after multiplying it comes 24.0
and that is equal to 24. (because after decimal zeros has no value)
3……….
and u also can multiply 2 by 60 . it occurs 120 then devide it by 5 . the answer comes 24.
Answer:
D. $3000
Step-by-step explanation:
Just did the test
Answer:
t =17 years
Step-by-step explanation:
The formula for interest
A = P(1+ r/n)^ nt
where a is the amount in the account , p is the principal, r is the rate, n is the number of times compounded per year and t is the time in years
Substituting in what we know
690 = 460 ( 1+ .024/365)^ 365t
690/460 = ( 1+ .024/365)^ 365t
1.5 = ( 1+ .024/365)^ 365t
Taking the log of each side
log(1.5) = 365t log( 1+ .024/365))
Dividing each side by( 1+ .024/365)
log(1.5)/ log( 1+ .024/365) = 365t
divide each side by 365
1/365 log(1.5)/ log( 1+ .024/365) =t
t =16.8949
To the nearest year
t =17
Answer:
Uh dude their are no questions??
Step-by-step explanation:
