Well, we can denote L and W for the length and width respectively. Lets say the A is the area, we have: 1. A=(L × W) as well as 2. 2(L+W)=400. We rearrange the second equation to get 3. W=200-L. From this, we can see that 0<L<200. Substitute the third equation into the first to get A=(200L-L²). put this formula into the scientific calculator and you will find a parabola with a maximum. That would be the maximum area of the enclosed area. Alternatively, we can say that L is between 0 and 200 when the area equals 0. (The graph you find will be area against length). As the maximum is generally found halfway, we substitute 100 into the equation and we end up with 10000.
Hope this helps.
Put the values of x to the equation of the function.
Answer:
I'm almost positive it's .A but I'm not sure
We know that
Right triangles PBM and MTF are similar
because
angle PMB=angle TMF
and
angle BPM=angle FTM
and
angle B =angle F=90 degrees
so
corresponding sides are
BM and MF
PB and TF
PM and MT
(PB/TF)=BM/MF
solve for PB
PB=(TF*BM)/MF
where
TF=6ft
BM=20 ft
MF=3 ft
so
PB=(6*20)/3------> 40 ft
the answer is
<span>the height of the peak is 40 ft</span>
X = half width of tent
Tan(40) = 6/x
x = 6/Tan(40) = 7.15
2x = 14.30 feet the width of the tent
