Question

What is the sum of the answers to the eqation?0%3D%200" id="TexFormula1" title=" {x}^{2} - 6x + 5 = 0" alt=" {x}^{2} - 6x + 5 = 0" align="absmiddle" class="latex-formula">
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Answer 1

x² - 6x + 5 = 0

x² - x - 5x + 5 = 0

x(x - 1) - 5(x - 1) = 0

(x - 5)(x - 1) = 0

x - 5 = 0 => x₁ = 5

x - 1 = 0 => x₂ = 1

Answer 2

Answer:

6

Step-by-step explanation:

$x^{2}$ - 6x +5 = 0

$x^{2}$ - 6x + 9 -9 +5 = 0

[$x^{2}$ - 6x + 9] - 4 =0

$(x -3)^{2}$ -4 = 0

$(x -3)^{2}$ = 4

(x-3) = $\sqrt{4}$ or (x-3) = - $\sqrt{4}$

(x-3) = 2 or (x-3) = -2

x = 5 or x = 1

therefore, sum of these solutions is 5+1 = 6