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3 years ago

2/7 - 3/2 for anyone that doesant know that’s a fraction am struggling on

Mathematics

1 answer:

enyata [817]3 years ago

7 0

Answer:

-17/14

Step-by-step explanation:

To subtract fractions, you must have a common denominator. If that is not given, you make it.

You do so buy finding the LCM of denominators:

LCM of 7 and 2 = 14

Now, here you have multiplied the denominators either by 7 or 2. You do the same for the respective numerators:

2x2/14 - 3x7/14 = 4/14 - 21/14.

Now that you have the same denominator, subtract the numerators:

4-21 = - 17

Put it back as a fraction : -17/14

hope this helps.

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Help me please!!!!!!!!

Vedmedyk [2.9K]

48 ÷ 200 = 0.24

0.24 × 25 = 6

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4 0

3 years ago

Mary's math certificate is 10 inches tall and 13 inches wide. Mary wants to put the certificate

wlad13 [49]

Answer:

$219.70

Step-by-step explanation:

First, you need to find the area of the certificate, which you can do by multiplying 10*13, since it is a rectangle. 10*13 is 130. Then, multiply 130 by the price per inch, which is $1.69. 130*1.69=219.7, which in financial terms would amount to $219.70.

8 0

3 years ago

Help im super confused on this question

Verizon [17]

Answer:

⦿ (7, 2)

Step-by-step explanation:

Try each solution in both inequalities and see which solution makes both inequalities true.

4x + 2y > 8

x - y ≥ 2

A. (2, 4)

4(2) + 2(4) > 8

16 > 8 True

2 - 4 ≥ 2

-2 ≥ 2 False

B. (4, 0)

4(-4) + 2(0) > 8

-16 > 8 False

C. (7, 2)

4(7) + 2(2) > 8

32 > 8 True

7 - 2 ≥ 2

5 ≥ 2 True

D. (1, -3)

4(1) + 2(-3) > 8

-2 > 8 False

Answer: C.

8 0

2 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

1. Which of the following describes the end behavior of the function ƒ(x) = x^4 + 3x^3 – 2x + 7?

snow_tiger [21]

Hello, when x tends to $\infty$ the term with the highest degree will lead the behaviour.

In other words.

$\displaystyle \lim_{x\rightarrow+\infty} {x^4+3x^3-2x+7}\\\\=\lim_{x\rightarrow+\infty} {x^4}\\\\=+\infty\\\\\\\displaystyle \lim_{x\rightarrow-\infty} {x^4+3x^3-2x+7}\\\\=\lim_{x\rightarrow-\infty} {x^4}\\\\=+\infty$

So, the answer B is correct.

Thank you.

6 0

3 years ago