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choli [55]
2 years ago
9

George has two dogs.

Mathematics
2 answers:
Stella [2.4K]2 years ago
7 0
Uhhhhhhhhhhhhhhhhhhhhhhhh
Daniel [21]2 years ago
3 0

the answer to this equation is 104.25

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Sketch the graph by hand using asymptotes and intercepts, but not derivatives. Then use your sketch as a guide to producing grap
Arisa [49]

The local minima of f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2} are (x, f(x)) = (-1.5, 0) and (7.980, 609.174)

<h3>How to determine the local minima?</h3>

The function is given as:

f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}

See attachment for the graph of the function f(x)

From the attached graph, we have the following minima:

Minimum = (-1.5, 0)

Minimum = (7.980, 609.174)

The above means that, the local minima are

(x, f(x)) = (-1.5, 0) and (7.980, 609.174)

Read more about graphs at:

brainly.com/question/20394217

#SPJ1

7 0
2 years ago
I NEED HELP I DONT KNOW THIS ANSWER
Papessa [141]

Answer:

Help with what

Step-by-step explanation:

4 0
2 years ago
Help me with this question!! I’m
topjm [15]

Step-by-step explanation:

there isn't any question if there would be i would answer

7 0
3 years ago
Read 2 more answers
Determine the vertical asymptote for the rational function f(x) = x - 4 over 2x - 3
k0ka [10]

Answer:

x = \frac{3}{2}

Step-by-step explanation:

Given

f(x) = \frac{x-4}{2x-3}

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

Thus x = \frac{3}{2} is the vertical asymptote

5 0
3 years ago
99 POINTS!!!! WRONG ANSWER GETS REPORTED!
jeka94
This is the correct answer

7 0
3 years ago
Read 2 more answers
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