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vitfil [10]
4 years ago
11

Since this object is traveling at terminal velocity, what must be the value of Fd? (HINT: how to the lengths of both arrows comp

are?)
Question options:

A. 0 Newtons


B. 425 Newtons


C. 850 Newtons


D. 1700 Newtons

Physics
1 answer:
Juli2301 [7.4K]4 years ago
8 0

The magnitude of the air drag when the object is traveling at terminal velocity is C. 850 Newtons

Explanation:

There are only two forces acting on the object here:

- The force of gravity, of magnitude F_g = 850 N, acting downward

- The air drag, F_d, acting upward

Therefore, the equation of motion for the object is

F_g - F_d = ma

where m is the mass of the object and a its acceleration.

The object in this problem is traveling at terminal velocity: this means that the acceleration is zero, so

a = 0

Therefore the equation becomes

F_d = F_g

which means that the magnitude of the air resistance is equal to the magnitude of the force of gravity:

F_d = 850 N

Learn more about acceleration and Newton laws of motion here:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

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What is the mass of a cannonball if a force of 2,500 N gives the cannonball an acceleration of 200m/s2?
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Newton's 2nd law of motion:

                         Force = (mass) x (acceleration)

Divide each side
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                                       =  (2,500 N)  /  (200 m/s²)

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8 0
4 years ago
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Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposi
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Consider velocity to the right as positive.

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m₁ = 4.0 kg
v₁ = 2.0 m/s to the right

Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left

Total momentum of the system is
P = m₁v₁ + m₂v₂
   = 4*2 + 8*(-3)
  = -16 (kg-m)/s

Let v (m/s) be the velocity of the center of mass of the 2-block system.

Because momentum of the system is preserved, therefore
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v = -1.333 m/s

Answer:
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According to Doppler Effect, an observer at rest will perceive a shift in the wavelength or frequency of the radiation emitted by a source in movement.This shift is given by the formula:
\frac{ \lambda - \lambda_{0} }{ \lambda_{0} } = \frac{-v}{c}

where:
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Therefore, we can solve for the observed wavelength:
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Substituting the given data:
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Hence, the observed wavelength of the line would be 655.80 nm. Note that this value is smaller than the one at rest, which means that we have a blue-shift, as expected for an approaching source.
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