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3 years ago

Which best describes two counteracting forces on an object

Physics

2 answers:

Natali5045456 [20]3 years ago

6 0

The correct answer is B two children pulling apart a wishbone

Let me know if you have any questions, and have a nice day!

Makovka662 [10]3 years ago

3 0

Answer:

B for Edgunity

Explanation:

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Answer A B C D and E

harina [27]

Answer:

what is the question I cannot click the

Explanation:

4 0

3 years ago

?/1 Jorge traveled 5 miles north to school. He then traveled 3 miles west to the store. Then he left the store and traveled 5 mi

aleksklad [387]

Answer:

He's 3 miles west of school.

Explanation:

He went 5 miles up and 5 miles down which means that he really didn't go up or down. In between that, he went 3 miles west so if the 5 milers don't count, this puts him at 3 miles west of school.

4 0

3 years ago

Where in the world does average daily temperature exceed the annual temperature range?

padilas [110]

The average daily annual temperature range is exceeded in places such as deserts. Deserts tend to be hotter due to the lack of water contained within them. This means that all of the sun's thermal radiation heats up the ground and air. These factors cause deserts to have above average temperatures.

6 0

3 years ago

the strength of the pulling force on the moon is 1/6 of that on earth whilst on Jupiter it is 2.5 times stronger what is the wei

KiRa [710]

Weight is the force exerted on an object by gravity. So, weight of any object on the moon is 1/6 that on Earth.

6 0

3 years ago

If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon-population sy

Genrish500 [490]

The question is incomplete. The complete question is :

If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon population system move? Assume the population is 7 billion, the average human has a mass of 65 kg, and that the population is evenly distributed over both the Earth and the Moon. The mass of the Earth is 5.97×1024 kg and that of the Moon is 7.34×1022 kg. The radius of the Moon’s orbit is about 3.84×105 m.

Solution :

Given :

Mass of earth, $M_e = 5.97 \times 10^{24} \ kg$

Mass of moon, $M_m = 7.34 \times 10^{22} \ kg$

Mass of each human, $m_p =65 \ kg$

Therefore mass of total population, $M_p = 65 \times 7 \times 10^{9} \ kg$

$M_p = 4.55 \times 10^{11} \ kg$

Let the earth is at the origin of the coordinate system. Then,

Since $M_e>> M_p$

$M_m>> M_p$

Hence if we shift all the population on the moon there will be negligible change in the mass of the moon and earth. Hence there will not be any significant shift on the centre of mass. i.e.

$X_{cm} = \frac{5.97 \times 10^{24}+ 7.34 \times 10^{22} \times 3.84 \times 10^5}{5.97 \times 10^{24}+ 7.34 \times 10^{22}}$

$= 4.68 \times 10^6 \ m$

$4.68 \times 10^3 \ km$ from the earth.

3 0

3 years ago