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3 years ago

What is the name of the part of the wave that is labeled -

Physics

1 answer:

tresset_1 [31]3 years ago

7 0

Answer:

amplitude

Explanation:

sound travel and it amplifies

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A calculator has a resistance of 22 Ω. What is the power rating for this calculator when connected to a 1.5 V battery?

GREYUIT [131]

Answer:

Explanation:

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3 years ago

A stunt cyclist rides on the interior of a cylinder 13 m in radius. The coefficient of static friction between the tires and the

ZanzabumX [31]

Answer:

$v=13.1m/s$

Explanation:

From the question we are told that:

Radius r=13

Coefficient of static friction \mu=0.67

Given the Centripetal concept

Generally the equation for Velocity v is mathematically given by

$v=\sqrt{\frac{gr}{\mu}}$

$v=\sqrt{\frac{9.81*13}{0.67}}$

$v=13.1m/s$

The value of the minimum speed (in m/s) for the cyclist to perform the stunt is Given as

$v=13.1m/s$

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3 years ago

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial spe

Novosadov [1.4K]

Consider horizontal component: Using the formula:v2=u2+2as
0=(16sin470)2+2(−9.81)ss=6.98m=7.0m(2s.f.)The maximu height from the ground is 8.5m

4 0

3 years ago

Satellite A orbits a planet at a distance d from the planet’s center with a centripetal acceleration a0. A second identical sate

leva [86]

To solve this problem it is necessary to use the concepts related to the Gravitational Force and Newton's Second Law, as far as we know:

$F_g = \frac{GMm}{r^2}$

Where,

G = Gravitational constant

M = Mass of earth (in this case)

m = mass of satellite

r = radius

In the other hand we have the second's newton law:

$F = ma$

Where,

m = mass

a = acceleration

Equation both equations we have,

$ma = \frac{GMm}{r^2}$

For the problem we have that,

Satellite A:

$ma_A = \frac{GMm}{r^2}$

Satellite B:

$ma_B = \frac{GMm}{(2r)^2}$

The ratio between the two satellites would be,

$\frac{ma_A}{ma_B}= \frac{\frac{GMm}{r^2}}{\frac{GMm}{(2r)^2}}$

Solving for a_B,

$a_B = \frac{a_A}{4}$

Therefore the centripetal acceleration of $A_B$ is a quarter of $a_A$

7 0

3 years ago

For each combination, record the total force, total mass, and acceleration. On the last column, multiply the mass (m) and accele

Sedaia [141]

Hello. You did not present the combinations the question refers to, which makes it impossible for this question to be answered accurately. However, I will try to help you in the best possible way.

To present the total force you must use the following formula: Mass x Acceleration.

To calculate the total mass, you must use the formula: Force / acceleration.

To calculate the acceleration you must use the formula: Force / mass.

8 0

3 years ago