What is the name of the part of the wave that is labeled -

a chuck wagon with an initial velocity of 4 m/s and a mass of 35 kg gets a push with 350 joules of force. what is the wagon's fi

Kitty [74]

Answer:

the final velocity of the wagon is 6 m/s.

Explanation:

Given;

initial velocity of the wagon, u = 4 m/s

mass of the wagon, m = 35 kg

energy applied to the wagon, E = 350 J

The final velocity of the wagon is calculated as;

E = ¹/₂m(v² - u²)

$m(v^2-u^2) = 2E\\\\v^2-u^2 = \frac{2E}{m} \\\\v^2 = \frac{2E}{m} + u^2\\\\v = \sqrt{\frac{2E}{m} + u^2} \\\\v = \sqrt{\frac{2(350)}{35} + (4)^2}\\\\v = 6 \ m/s$

Therefore, the final velocity of the wagon is 6 m/s.

8 0

3 years ago

What is the amount of thermal energy that can be stored in an object depends on?

77julia77 [94]

Thermal energy is the total energy of all the molecules in an object. The thermal energy of an object depends on three things: 4 the number of molecules in the object 4 the temperature of the object (average molecular motion) 4 the arrangement of the object's molecules (states of matter).

Hope this helps

3 0

3 years ago

A tank holds a 1.44-m thick layer of oil that floats on a 0.98-m thick layer of brine. Both liquids are clear and do not intermi

denpristay [2]

Answer:

Angle of ray makes with the vertical is 62.1 degree

Explanation:

As per the ray diagram we know that the angle of incidence on oil brine interface will be given as

$tan\theta_i = \frac{0.7}{0.98}$

$\theta_i = 35.5^0$

now by Snell'a law at that interface we have

$\mu_1 sin\theta_i = \mu_2 sin \theta_r$

now we will have

$1.52 sin35.5 = 1.40 sin\theta_r$

$\theta_r = 39.12^0$

now this is the angle of incidence for oil air interface

so now again by Snell's law we will have

$\mu_2 sin\theta_i' = \mu_{air} sin\theta$

$1.40 sin39.12 = 1 sin\theta$

$\theta = 62.1^0$

3 0

3 years ago

How would "you" define critical thinking?

nasty-shy [4]

Answer:

Critical thinking is the analysis of facts to form a judgment. The subject is complex, and several different definitions exist, which generally include the rational, skeptical, unbiased analysis, or evaluation of factual evidence

Explanation:

8 0

3 years ago

The potential difference across a resistor increases by a factor of 2. How does the current change? (Ohm's law: V = IR) A. It de

Sedaia [141]

The answer is C.

The question says the potential difference is what is changing, which means we're solving for V.

It tells us that potential difference increases by a factor of two, which just means V doubles.

With this info, we can pick some numbers, plug it into Ohms law and see what happens.

Here's an example where I just picked random numbers that are easy to work with:

V=I*R
10=I*5
I=2
Lets increase the potential difference (V) by a factor of two and see what happens to current:
V=I*R
20=I*5 (all I've done is double the potential difference from 10 to 20)
I=4

When we increase V by a factor of 2, I increases by a factor of 2. We went from I=2 to I=4.
We can increase V by factor of 2 again and see:
V=I*R
40=I*5
I=8

Okay, current just increased by a factor of 2 again when we increased the potential difference by a factor of 2.

It's always good to check work with alternate numbers, so here's one more set:
V=I*R
16=I*4
(remember, we know we're solving for V, so I'm just plugging in random numbers for I and R)
I=4
Increase V by factor of 2:
32=I*4
I=8

So, when we increase V (the potential difference) by a factor of 2, I (current) always increases by a factor of 2 as well.

Hope this helps!

3 0

3 years ago

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