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Sergio039 [100]
3 years ago
15

When an object's final velocity is less than its initial velocity, however, it has ________________ acceleration.

Physics
1 answer:
algol [13]3 years ago
4 0

Answer:

The body has negative acceleration PR a deceleration.

Explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

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Question 2 (1 point)
MaRussiya [10]

Answer:

4.4694 meters per second, 74.4907 kilometers per hour.

3 0
3 years ago
An object moves 4 meters north, then 3 meters east. What is the displacement of the object?
Lady bird [3.3K]

The displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.

<h3>What is displacement?</h3>

Displacement is change in the position of an object. It can be described as the shortest distance between the initial and final position of an object.

The displacement of the object is calculated as follows;

d² = 4² + 3²

d² = 25

d = 5 m

Thus, the displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.

Learn more about displacement here: brainly.com/question/2109763

#SPJ2

4 0
2 years ago
Read 2 more answers
What was the problem that led scientists to explore genetic engineering as a solution?
Artyom0805 [142]
<span>Genetic engineering was a solution to drought
This website will help you...
</span><span>https://www.weforum.org/agenda/2014/08/genetic-engineering-drought-irrigation-regulations/I hope this helped! (The picture is nothing special. But if you looked at the website above, you would look like it!)

<span>
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4 0
3 years ago
The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
Colt1911 [192]

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb

Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

∑'MA = 0

⇒ NB [Lsin∅] - W[L/2.cos∅] = 0

NB = W / 2tan∅ -------let this be equation 1

∑Fx = 0

⇒ FA - NB = 0

FA = NB

therefore from equation 1

FA = NB = W / 2tan∅

we substitute in our values

FA = NB = 76 / 2tan(60°) = 21.9393 lb

Now ∑Fy = 0

NA - W = 0

NA = W = 76 lb

Net force at A will be

FA' = √( NA² + FA²)

= √( (W)² + (W / 2tan∅)²)

we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

= √ 6257.3328

FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

5 0
3 years ago
How does current flow in a standard DC circuit?
KATRIN_1 [288]

Answer:

A

Explanation:

4 0
3 years ago
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