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Aleksandr-060686 [28]
3 years ago
10

The school principal decided to put a small fence around the hopscotch area

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
6 0
She can make a 6x7 or a 7x6 area

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What is the circumference of a circle that has the radius of 3cm​
dexar [7]

Step-by-step explanation:

Circumference of a circle is 2piR

Here R is 3 cm

So C=2pi(3)

C=6pi cm

5 0
3 years ago
What is the function transformation between f(x)=4x+5 and g(x)=- 4x+7 ?
nirvana33 [79]

Answer:

2

Step-by-step explanation:

8 0
3 years ago
Find the least mean square estimate ofxbased on the observationy=y.
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3 years ago
Mason and Laney run laps. The ratio of the number of laps Mason ran to the number Laney ran was 2:3.
3241004551 [841]

Using proportions, it is found that Mason ran 620 meters.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Considering the ratio, the <em>rule of three</em> is given as follows:

2 laps for Mason - 3 laps for Laney.

n meters for Mason - 930 meters for Mason.

Applying cross multiplication:

3n = 930 x 2

n = 930 x 2/3

n = 620

Mason ran 620 meters.

More can be learned about proportions at brainly.com/question/24372153

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3 0
2 years ago
A survey is made to determine the number of households having electric appliances in a certain city. It is found that 75% have r
Mashcka [7]

Answer:

The probability that a household has at least one of these appliances is 0.95

Step-by-step explanation:

Percentage of households having radios P(R) = 75% = 0.75

Percentage of households having electric irons P(I) = 65% = 0.65

Percentage of households having electric toasters P(T) = 55% = 0.55

Percentage of household having iron and radio P(I∩R) = 50% = 0.5

Percentage of household having radios and toasters P(R∩T) = 40% = 0.40

Percentage of household having iron and toasters P(I∩T) = 30% = 0.30

Percentage of household having all three P(I∩R∩T) = 20% = 0.20

Probability of households having at least one of the appliance can be calculated using the rule:

P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)

P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20  P(at least one of the three) = 0.95

The probability that a household has at least one of these appliances is 0.95

3 0
3 years ago
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