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3 years ago

The school principal decided to put a small fence around the hopscotch area

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

6 0

She can make a 6x7 or a 7x6 area

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Write an equation for the line (4,7) and ( 1,1)2. Write an equation for the graph

Nastasia [14]

ANSWER:

$y=2x-1$

STEP-BY-STEP EXPLANATION:

We have that the equation in its slope-intercept form is the following:

$\begin{gathered} y=mx+b \\ m\text{ is the slope and b is the y-intercept } \end{gathered}$

The slope can be calculated as follows:

$m=\frac{y_2-y_1}{x_2-x_1}$

We use the points (4,7) and (1,1) to calculate the slope:

$m=\frac{1-7}{1-4}=\frac{-6}{-3}=2$

Now, we calculate the value of b, using the point (1,1) and the slope, like this:

$\begin{gathered} 1=1\cdot2+b \\ b=-2+1 \\ b=-1 \end{gathered}$

Therefore, the equation would be:

$y=2x-1$

5 0

9 months ago

My question is what is 8.7+5.4

alex41 [277]

The awnser to this question is 14.1

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3 years ago

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A graph titled Swimmers at City Pool has Temperature (degrees Fahrenheit) on the x-axis, and swimmers on the y-axis. A trend lin

aniked [119]

Answer:

25 is the answer

7 0

2 years ago

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Please answer this question.

Kaylis [27]

Combine the like terms
-x-x^2+7

4 0

3 years ago

PLEASE HELP I NEED THIS ASAP<br> Find the vertex of y=x^2-7x+4

Goshia [24]

Answer:

$\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$

Step-by-step explanation:

$y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\$

$\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$

6 0

3 years ago