Answer:
I think the answers is B
Step-by-step explanation:
But im so sorry if its not right...
<em>H</em><em>a</em><em>v</em><em>e</em><em> </em><em>a</em><em> </em><em>n</em><em>i</em><em>c</em><em>e</em><em> </em><em>d</em><em>a</em><em>y</em>
The answer is C.) y=2x+1 since the slope is going upward, and will match the scatter plot.
(a) You can parameterize <em>C</em> by the vector function
<em>r</em><em>(t)</em> = (<em>x(t)</em>, <em>y(t)</em> ) = <em>P</em> (1 - <em>t </em>) + <em>Q</em> <em>t</em> = (2 - 2<em>t</em>, 7<em>t</em> )
where 0 ≤ <em>t</em> ≤ 1.
(b) From the above parameterization, we have
<em>r</em><em>'(t)</em> = (-2, 7) ==> ||<em>r</em><em>'(t)</em>|| = √((-2)² + 7²) = √53
Then
d<em>s</em> = √53 d<em>t</em>
and the line integral is

(c) The remaining integral is pretty simple,

Answer:
(4,5)
Step-by-step explanation:
Hello!
If you move 5 units to the left, you change the x-value in (x, y) by -5.
Let the original x-value be x:
The original x-value is 4. Since you didn't change the y-value (up/down), you can keep the same y-value for the coordinate.
The original point was at (4,5)