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icang [17]
3 years ago
10

The Tigers have win-to-lost ratio of 2:3. The Gulls have a win-to-total game ratio of 1:2. Who has the better ratio of wins-to-t

otal games?
Mathematics
2 answers:
Whitepunk [10]3 years ago
6 0
Tiger:
Win : Lost : Total
  2   :   3    :    5
(x3)   (x3)
  6   :   9    :    15
  
Gull:
Win : Lost : Total
  1       2    :    3
(x5)   (x5)
  5   :   10    :  15

Tiger →Win : Total →  6:15
Gull  → Win : Total  → 5:15

If both played a total of 15 games, Tiger has a 6 wins chance whereas Gull has 5 wins chance.

Answer: Tiger


Helga [31]3 years ago
3 0
We need to compare ratios

2/3 and 1/2

make the same denominator

2/3= 4/6
1/2=3/6
4/6>3/6
so 2/3 >1/2
2/3 better ratio (Tigers)
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Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

Step-by-step explanation:

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P = \frac{1,000}{300,000,000} = 0.000003 = 0.0003%

So, we have these following probabilities:

A 99.9997% probability that a randomly chosen person is not a terrorist.

A 0.0003% probability that a randomly chosen person is a terrorist.

A 98% probability that a future terrorist is correctly identified

A 99.9% chance of correctly identifying someone who is not a future terrorist. This also means that there is a 0.01% probability of someone who is not a terrorist being identified as one.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

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What is the probability that the person is a terrorist, given that she was identified as a terrorist.

P(B) is the probability that the person is a terrorist. So P(B) = 0.000003

P(A/B) is the probability that the person was identified as a terrorist, given that she is a terrorist. The problem states that the system has a 98% chance of correctly identifying a future terrorist, so P(A/B) = 0.98

P(A) is the probability of a person being a identified as a terrorist. So

P(A) = P_{1} + P_{2}

P_{1} is the probability that a person is a terrorist and was identified as one. So:

P_{1} = 0.000003*0.98 = 0.00000294

P_{1} is the probability that a person is not a terrorist and, but was identified as one. So:

P_{2} = 0.999997*0.0001 = 0.0000999997

So

P(A) = P_{1} + P_{2} = 0.00000294 + 0.0000999997 = 0.000103

The answer is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.000003*0.98}{0.000103} = 0.028544

Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

3 0
3 years ago
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