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pantera1 [17]
3 years ago
13

Write the equation 6x + 2y = 4 in slope-intercept form.

Mathematics
2 answers:
AveGali [126]3 years ago
7 0
Y=-3x+2 would be the answer!
Mademuasel [1]3 years ago
3 0
The slope of 6x + 2y = 4 is
y = -3x + 2
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I'm lost on this please help
Natasha2012 [34]

Answer:

integer-4

proper fraction-1/10

improper fraction-0/4

Step-by-step explanation:

do not copy in the internet

8 0
3 years ago
I need some help... Algebra Hw
Svet_ta [14]

Answer:can't see no 1

Step-by-step explanation:

2=A

3=c

4 0
3 years ago
Select all the expressions that are equivalent to 9 + 7x – 3y. 9 + 7x + 3y 9 – 7x – 3y 9 – 7x + 3y 9 + 7x + (–3y) 9 – (–7)x – 3y
bulgar [2K]

0^9 +7x+189yx−3y

o

9

+7x−3y

9

+7x+3y

9

−7x−3y

9

−7x+3y

9

+7x+189yx−3y

2 Collect like terms.

{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y

o

9

+(7x+7x−7x−7x+7x)+(−3y

9

+3y

9

−3y

9

+3y

9

)+189yx−3y

3 Simplify.

{o}^{9}+7x+189yx-3y

o

9

+7x+189yx−3y

6 0
2 years ago
A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the
Kay [80]

Answer:  The required number of quarters in the collection is 11.

Step-by-step explanation:  Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05,   1 dime = $ 0.10   and    1 quarter = $0.25.

Then, according to the given information, we have

x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)

and

y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)

Comparing the values of y from equations (iv) and (v), we get

47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.

Thus, the required number of quarters in the collection is 11.

7 0
2 years ago
Order least to greatest: 1.5, 1.1, .9, 1, 1.7, 1.25
avanturin [10]

Answer:

1,1.1,1.25,1.5,1.7,9

8 0
3 years ago
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