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Diano4ka-milaya [45]
3 years ago
7

Find the values of y = p(x) = √x for x = 0, 1.44, 2.25, 3.24, 4.41, 5.29

Mathematics
1 answer:
zhenek [66]3 years ago
6 0
P(x) = √x


for x = 0 → √0 = 0 and p(0) = 0
for x = 1.44 → √1.44 =1.2  and p(1.44) = 1.2
for x = 2.25 → √2.25 = 1.5 and p(2.25) = 1.5
for x = 3.24 → √3.24 = 1.8 and p(3.24) = 1.8
for x = 4.41 → √4.41=  2.1 and p(4.41) = 2.1
for x = 5.29 → √5.29 = 2.3 and p(5.29) = 2.3

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The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –
Brrunno [24]

The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

-5a^2b^2 +12a^2b - 5

Let suppose the other polynomial addend is f(a,b). Thus,

(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)

Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

7 0
2 years ago
Please help, thank you!!
julsineya [31]

Answer:

Step-by-step explanation:

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A = Base * height / 2

Solution

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4 0
3 years ago
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