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siniylev [52]
4 years ago
15

Solve for the problem 13^3x-1=91

Mathematics
1 answer:
gogolik [260]4 years ago
7 0

Answer:

{13}^{3} x - 1 = 91 \\  {13}^{3}x = 91 - 1 \\  {13}^{3}x   = 90 \\  2,197x = 90 \\  \frac{2197x}{2197}  =  \frac{90}{2197}  \\ x = 0.04

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I need help with this problem. ​
MariettaO [177]

Answer:

the numbers next to a variable is a coefficient, for instance in 2x 2 would be the coefficient.

the constants are the numbers without variables next to them, just numbers

like terms are the term that are similar like 2x and 8x or even 5 and 3

lm not exactly sure what they mean when asking for constant terms.

4 0
3 years ago
(I WILL MARK BRAINLY)
Mademuasel [1]

Answer:

Step-by-step explanation:

light blue, 4,6,8

5 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
BaLLatris [955]

Answer:

a₆ ≈ 25.284

Step-by-step explanation:

There is a common ratio between consecutive terms , that is

8 ÷ 6 = \frac{32}{3} ÷ 8 = \frac{4}{3}

This indicates the sequence is geometric with nth term

a_{n} = a₁ r^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r = \frac{4}{3} , then

a₆ = 6 × (\frac{4}{3}) ^{5} = 6 × \frac{1024}{243} = \frac{6(1024)}{243} ≈ 25.284 ( to the nearest thousandth )

6 0
2 years ago
Read 2 more answers
What is the volume (in cubic units) of a cylinder with a radius of
Contact [7]
It would be 339.1 hope this helps
4 0
2 years ago
For the Rule of 78, for a 12-month period, the last term in the sequence is 12 and the series sums to 78. For an 10 month period
Svetllana [295]
For a 10 month period the last term is 10 and the series sum is 55. For a 15 month period the last term is 15 and the sum is 120. For a 20 month period the last term is 20.
If u want the sum then it is 210.

Hope this helps you!
5 0
3 years ago
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