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telo118 [61]
3 years ago
13

Describe how to prepare the following solutions using solid sodium iodide, liquid water and common laboratory equipment (balance

, spatulas, volumetric flasks, pipets, beakers, etc)
a) 200mL of 0.16M NaI
b) 200mL of 0.16m NaI
c) 200mL of o.16% mass NaI​
Chemistry
1 answer:
Zinaida [17]3 years ago
5 0

Answer:

b

Explanation:

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What is the molecule shown below?
FrozenT [24]

Answer:

2,3–dimethylpentane

Explanation:

To know which option is correct, we shall determine the name of the compound.

To obtain the name of the compound, do the following:

1. Determine the longest continuous carbon chain. This gives the parent name of the compound.

2. Identify the substituent group attached to the compound.

3. Locate the position of the substituent group by giving it the lowest possible count.

4. Combine the above to obtain the name of the compound.

Now, we shall determine the name of the compound as follow:

1. The longest continuous carbon chain is 5. Thus, the parent name of the compound is pentane.

2. The substituent group attached is methyl (–CH₃)

3. There are two methyl group attached to the compound. One is located at carbon 2 and the other at carbon 3.

4. Therefore, the name of the compound is:

2,3–dimethylpentane

None of the options are correct.

8 0
3 years ago
1. A cold front forms when-
Aleks [24]
A cold air mass moves into an area of warm air
4 0
3 years ago
What is the longest wavelength in the Balmer series? (Hint: the Rydberg constant for Hydrogen is 1.096776×107 1/m, and the Balme
boyakko [2]

<u>Answer:</u> The longest wavelength of light is 656.5 nm

<u>Explanation:</u>

For the longest wavelength, the transition should be from n to n+1, where: n = lower energy level

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.096776\times 10^7m^{-1}

n_f = Higher energy level = n_i+1=(2+1)=3

n_i= Lower energy level = 2    (Balmer series)

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.096776\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.5233\times 10^6m^{-1}}=6.565\times 10^{-7}m

Converting this into nanometers, we use the conversion factor:

1m=10^9nm

So, 6.565\times 10^{-7}m\times (\frac{10^9nm}{1m})=656.5nm

Hence, the longest wavelength of light is 656.5 nm

4 0
3 years ago
This is the measure of the quantity of matter
Akimi4 [234]

Answer : Mass

Explanation : Mass measures the amount of matter in a substance or an object.

3 0
3 years ago
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What experiments did Lavoisier do?
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He did experiments with combustion and gas's
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