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SCORPION-xisa [38]
3 years ago
11

how does the involvement of energy in a decomposition reaction compare to how energy is involved in a combustion reaction?

Chemistry
1 answer:
MatroZZZ [7]3 years ago
8 0
A decomposition reaction produces multiple products from a single reactant.
Combustion reactions are the combination of some compound with oxygen to make oxides of the other elements as products (although nitrogen atoms react to make N2).
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Which gas will have the most collisions between its particles?
adoni [48]

Answer:

The gas is Methane at 340K

4 0
3 years ago
How do consumers obtain the carbon that they need for their life processes?
11111nata11111 [884]

Answer:

B

Explanation:

Edg

3 0
3 years ago
Read 2 more answers
The surface area of an object to be gold plated is 49.8 cm2 and the density of gold is 19.3 g/cm-3. A current of 3.15. A is appl
garik1379 [7]

Answer: Time required to deposit an even layer of gold with given thickness is 5.3 \times 10^{2} sec.

Explanation:

The given data is as follows.

     Surface area = 49.8 cm^{2},

     Density of gold = 19.3 g/cm^{3},

     Current = 3.15 A,       thickness of gold layer = 1.2 \times 10^{-3} cm

It is known that relation between volume, area and thickness is as follows.

           V = Surface area × Thickness

               = 49.8 \times 1.2 \times 10^{-3} cm

               = 0.05988 cm^{3}

Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.

  0.05988 \times cm^{3} \times \frac{19.3 g Au}{1 cm^{3}} \times \frac{1 mol Au}{197 g Au} \times \frac{3 mol e^{-}}{1 mol Au} \times \frac{96485}{1 mol e^{-}} \times \frac{1 As}{1 C} \times \frac{1}{3.20 A}

        = 5.3 \times 10^{2} sec

Thus, we can conclude that time required to deposit an even layer of gold with given thickness is 5.3 \times 10^{2} sec.

4 0
3 years ago
A formulation scientist is creating a formula for a new product that requires the following compounds: barium chloride, silicon
grandymaker [24]

Answer:

Yes. These chemicals named barium chloride and calcium carbonate have been named properly. But silicon oxide has not been named correctly, an oxide of silicon is named as silicon dioxide not silicon oxide.

Explanation:

In chemistry while naming chemicals there are certain rules and naming the chemicals as per these rules is known as chemical nomenclature. The IUPAC's rule for chemical nomenclature of inorganic compounds can be read in a book named as red book.

<u>By sign convention, a cation is named first followed by an anion.</u> For example, in barium chloride (BaCl₂), barium which is represented by symbol Ba²⁺ is a cation and therefore written before chloride (Cl⁻) which is an anion. Similarly calcium carbonate is represented as CaCO₃.

As per the valency of silicon, it forms a dioxide with oxygen atom and it is represented as SiO₂.

4 0
3 years ago
Are rocks on Earth's surface stable? What might cause rocks to change? Explain your reasoning.
zysi [14]

Answer:

All rocks are constantly moving, but at a pace we cant see. Rocks might change from weather corrosion, or magma moving deep down. They are stable but sometimes can be unstable (earthquakes).

Explanation:

6 0
3 years ago
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