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SCORPION-xisa [38]
2 years ago
11

how does the involvement of energy in a decomposition reaction compare to how energy is involved in a combustion reaction?

Chemistry
1 answer:
MatroZZZ [7]2 years ago
8 0
A decomposition reaction produces multiple products from a single reactant.
Combustion reactions are the combination of some compound with oxygen to make oxides of the other elements as products (although nitrogen atoms react to make N2).
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Calculate Density:<br> Volume=13cm3, Mass=147.55g<br> Someone please help
almond37 [142]

Answer:

11.35 g/cm³

Explanation:

If your rounding then 11.4. hope this helps :)

5 0
3 years ago
Calculate the empirical formula of a compound that has a composition of 5.9% (by mass) hydrogen and 94.1% (by mass) oxygen.​
adelina 88 [10]

Answer:

The empirical formula is the simplest form;

Given:

Oxygen O at 94.1% and

H at 5.9%

Assume 100grams.

94% = 0.941 x 100gm. = 94.1 gm x 1mole/16gm. = 5.88 moles of O

5.9% = 0.059 x 100gm. = 5.9gm. X 1moleH/1.002gm. = 5.88 moles of H

There is one mole of O for each mole of H so the empirical formula is O_1H_1

and written as OH.

8 0
3 years ago
Read 2 more answers
Why burning of fuel is a chemical change give 5 reasons to support your answer
frozen [14]

Answer:

Explanation:

1. New substances such as carbondioxide and water is formed.

2. There is evolution of gas bubbles. Gases are released.

3. There is either the absorption of energy or release of energy in form of light and energy.

4. The reaction is irreversible i.e it cannot be reversed, it is permanent once the reaction take place.

5. There is a change in both odor and smell.

A chemical change is a change where new substances are formed due to changes in the properties.

6 0
3 years ago
Find the grams in 1.26*10^-4 mol of HC2H3O2
Oksana_A [137]

Answer:

0.00757 grams

Explanation:

Find the molar mass of the compound: which is 60.05.

The molar mass is basically just the sum of all the atomic masses of each of the elements.

Then multiply the molar mass by the number of moles in the compound, which is 1.26 x 10^-4 moles.

Your answer should be 0.00757 grams.

5 0
3 years ago
The lock-and-key model and the induced-fit model are two models of enzyme action explaining both the specificity and the catalyt
ivolga24 [154]

Answer:

The lock-and-key model:

c. Enzyme active site has a rigid structure complementary

The induced-fit model:

a. Enzyme conformation changes when it binds the substrate so the active site fits the substrate.

Common to both The lock-and-key model and The induced-fit model:

b. Substrate binds to the enzyme at the active site, forming an enzyme-substrate complex.

d. Substrate binds to the enzyme through non-covalent interactions

Explanation:

Generally, the catalytic power of enzymes are due to transient covalent bonds formed between an enzyme's catalytic functional group and a substrate as well as non-covalent interactions between substrate and enzyme which lowers the activation energy of the reaction. This applies to both the lock-and-key model as well as induced-fit mode of enzyme catalysis.

The lock and key model of enzyme catalysis and specificity proposes that enzymes are structurally complementary to their substrates such that they fit like a lock and key. This complementary nature of the enzyme and its substrates ensures that only a substrate that is complementary to the enzyme's active site can bind to it for catalysis to proceed. this is known as the specificity of an enzyme to a particular substrate.

The induced-fit mode proposes that binding of substrate to the active site of an enzyme induces conformational changes in the enzyme which better positions various functional groups on the enzyme into the proper position to catalyse the reaction.

4 0
3 years ago
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