Answer:
The correct answer is the last statement.
Explanation:
Amphipathic refers to a substance that comprises both hydrophobic and hydrophilic surfaces. Thus, the given first three statements are incorrect. The amphipathic helices are witnessed on the proteins surfaces in which the hydrophilic region associates with the aqueous phase and the hydrophobic regions associate with the hydrophobic component of the protein.
Both the amphipathic sheets and helices exhibit primarily the hydrophobic or hydrophilic residues on one face. Thus, the correct answer is the last statement.
Answer:
12 : 3 : 1
Explanation:
According to Mendel's principles, a dihybrid cross between two heterozygous summer squash parents (WwGg X WwGg) should yield offsprings, 12 with white, 3 with yellow and 1 with green color phenotype. The classic Mendelian phenotypic ratio for dihybrid cross is 9:3:3:1. In this case, genotypes W- G- and W- gg produce white color phenotype. This is because we have 12: 3: 1 phenotypic ratio in which the alleles of two different genes assort independently into gametes.
<em>Dihybrid cross for heterozygous summer squash:</em>
WG Wg wG wg
WG WWGG WWGg WwGG WwGg
Wg WWGg WWgg WwGg Wwgg
wG WwGG WwGg wwGG wwGg
wg WwGg Wwgg wwGg wwgg
Genotypes:
W-G- and W- gg = white = 12
ww G- = yellow = 3
ww gg = green = 1
<span>Standard reduction potential is the likelihood that a species will be reduced. It is written in the form of a reduction half reaction.
</span>Lithium <span> has the lowest standard reduction potential.</span>
Answer:
The correct answer would be - there will be wild type and double mutant (contains both the deletion mutation and the point mutation)
Explanation:
It is mention that the deletion mutation and point mutation are non-overlapping or no overlapping regions in the phage genome. A crossing-over event between the regions of these two mutations would get wild-type which means there would be neither point mutation nor deletion mutation and other would be a double mutant that contains both mutation - the point mutation and the deletion mutation.
Thus, the correct answer is - there will be wild type and double mutant (contains both the deletion mutation and the point mutation)
