Here is what your frequency/cumulative frequency table would look like. The cumulative frequency is where you add all the frequencies from before it to get a sum after each interval.
<u> Frequency </u> <u>Cumulative Frequency</u>
0-25 8 8
26-50 0 8
51-75 4 12
76-100 2 14
С = 2πr [π≈3.14]
220 = 2 * 3.14 * r
220 = 6.28r
r = 220/6.28 ≈ 35 cm ← <span>to the nearest whole number.</span>
The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;
- Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.
- Maximum volume of the box is approximately 1048.6 in.³
<h3>How can the dimensions and volume of the box be calculated?</h3>
The given dimensions of the cardboard are;
Width = 18 inches
Length = 35 inches
Let <em>x </em>represent the side lengths of the cut squares, we have;
Width of the box formed = 18 - 2•x
Length of the box = 35 - 2•x
Height of the box = x
Volume, <em>V</em>, of the box is therefore;
V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x
By differentiation, at the extreme locations, we have;

Which gives;

6•x² - 106•x + 315 = 0

Therefore;
x ≈ 4.55, or x ≈ -5.55
When x ≈ 4.55, we have;
V = 4•x³ - 106•x² + 630•x
Which gives;
V ≈ 1048.6
When x ≈ -5.55, we have;
V ≈ -7450.8
The dimensions of the box that gives the maximum volume are therefore;
- Width ≈ 18 - 2×4.55 in. = 8.89 in.
- Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.
- The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³
Learn more about differentiation and integration here:
brainly.com/question/13058734
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You can't solvd monomials because they are just 1 term multiplication :
example: 2a , or 14
1)96/8=12
2)(95*6+5)/6 : (24+1)/3 = (95*6+5)/6 : 2*25/6 = 575/6 *6/50=575/50
=23/2=11 1/2
11 1/2
3) (11 1/2)*12 area of the one type of the wall, there are 2 such walls
(11 1/2)*12*2
(8 1/3)*12 area of the second type of the wall, there are 2 such walls
(8 1/3)*12 *2
Altogether area of the walls:
(11 1/2)*12*2 + (8 1/3)*12 *2=12*2(11 1/2 + 8 1/3)= =24(19+3/6+2/6)=24(19+5/6) = 456 +24*(5/6)= 456+20= 476
Tamara needs total 476 square feet, which is less than 480 square feet, so she has enough paint.