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NISA [10]
3 years ago
15

Three sisters each purchase two dresses and a purse. The purse costs 26.00. If the grand total was 205.50, how much did each dre

ss cost
Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0
205.50-26= 179.5
179.5/2= 89.75 $ for each dress
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The following list shows the number of video games sold per day at a video store.
TEA [102]
Here is what your frequency/cumulative frequency table would look like.  The cumulative frequency is where you add all the frequencies from before it to get a sum after each interval.

              <u> Frequency    </u>       <u>Cumulative Frequency</u>
0-25             8                              8
26-50           0                              8
51-75           4                             12
76-100         2                             14
4 0
3 years ago
A circular mat has a circumference of 220 centimeters. Find the radius rounded to the nearest whole number.
Papessa [141]
С = 2πr  [π≈3.14]

220 = 2 * 3.14 * r
220 = 6.28r 
r = 220/6.28 ≈ 35 cm  ←  <span>to the nearest whole number.</span>
6 0
3 years ago
I'm have some issues with the problem shown in the screenshot and would love some help.
KiRa [710]

The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;

  • Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.

  • Maximum volume of the box is approximately 1048.6 in.³

<h3>How can the dimensions and volume of the box be calculated?</h3>

The given dimensions of the cardboard are;

Width = 18 inches

Length = 35 inches

Let <em>x </em>represent the side lengths of the cut squares, we have;

Width of the box formed = 18 - 2•x

Length of the box = 35 - 2•x

Height of the box = x

Volume, <em>V</em>, of the box is therefore;

V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x

By differentiation, at the extreme locations, we have;

\frac{d V }{dx}  =  \frac{d( 4 \cdot \:  {x}^{3}  - 106 \cdot \:  {x}^{2}  + 630\cdot \:  {x} )  }{dx} = 0

Which gives;

\frac{d V }{dx}  =12\cdot \:  {x}^{2}  -  212\cdot \:  {x} + 630 = 0

6•x² - 106•x + 315 = 0

x  =  \frac{ - 6 \pm \sqrt{106 ^2 - 4 \times 6 \times 315} }{2 \times 6}

Therefore;

x ≈ 4.55, or x ≈ -5.55

When x ≈ 4.55, we have;

V = 4•x³ - 106•x² + 630•x

Which gives;

V ≈ 1048.6

When x ≈ -5.55, we have;

V ≈ -7450.8

The dimensions of the box that gives the maximum volume are therefore;

  • Width ≈ 18 - 2×4.55 in. = 8.89 in.

  • Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.

  • Height = x ≈ 4.55 in.

  • The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³

Learn more about differentiation and integration here:

brainly.com/question/13058734

#SPJ1

7 0
1 year ago
How to solve monomials
rewona [7]
You can't solvd monomials because they are just 1 term multiplication :
example: 2a , or 14
8 0
3 years ago
!*I NEED HELP AND QUICK*!
rewona [7]
1)96/8=12
2)(95*6+5)/6 : (24+1)/3 = (95*6+5)/6 : 2*25/6 = 575/6 *6/50=575/50
=23/2=11 1/2
11 1/2

3) (11 1/2)*12 area of the one  type of the wall, there are 2 such walls
 (11 1/2)*12*2
(8 1/3)*12 area of the second type of the wall, there are 2 such walls
(8 1/3)*12 *2

Altogether area of the walls:
(11 1/2)*12*2 + (8 1/3)*12 *2=12*2(11 1/2 + 8 1/3)= =24(19+3/6+2/6)=24(19+5/6) = 456 +24*(5/6)= 456+20= 476

Tamara needs total 476  square feet, which is less than 480 square feet, so she has enough paint.



5 0
3 years ago
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