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2 years ago

8

A human heart beats approximately 60 times per minute. If a man lives to the age of 90, how many times will his heart in his lif

etime.

1 answer:

makkiz [27]2 years ago

7 0

Answer:

90 Years = 47,304,000 Minutes = 47304000 Minutes.

Step-by-step explanation:

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Find the unit rate with the numbers 12 and one and one half

kati45 [8]

Answer:

The value of the unit rate is 8

Step-by-step explanation:

we know that

To calculate the unit rate simply divide the first number by the second number

so

$12:1\frac{1}{2}$

Convert mixed number to an improper fraction

$1\frac{1}{2}=1+\frac{1}{2}=\frac{1*2+1}{2}=\frac{3}{2}$

substitute in the expression above

$12:\frac{3}{2}=\frac{24}{3}=8$

4 0

2 years ago

Enter the sum of numbers as a product of their GCF.75 + 90

Semmy [17]

The gcf of the numbers are 15

5 0

2 years ago

two pumps of different sizes, working together, can empty a fuel tank in 3 hours. the larger pump can empty the tank in 4 hours

bonufazy [111]

Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.

8 0

3 years ago

Read 2 more answers

80 dollars for 16 tickets written as a unit rate, what is it?

shepuryov [24]

Answer:

5 dollars a ticket. Divide 80/16 to get tour answer.

Step-by-step explanation:

5 0

1 year ago

Read 2 more answers

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Ksju [112]

Answer:converge at $I=\frac{1}{3}$

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int^{\infty}_{3}\frac{1}{x^2}dx$

integration of $\frac{1}{x^2}$ is - $\frac{1}{x}$

$I=\left [ -\frac{1}{x}\right ]^{\infty}_3$

substituting value

$I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]$

$I=-\left [ 0-\frac{1}{3}\right ]$

$I=\frac{1}{3}$

so the value of integral converges at $\frac{1}{3}$

8 0

3 years ago