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AleksandrR [38]
3 years ago
12

If you roll two fair six-sided dice, what is the probability that the sum is 5 or lower?

Mathematics
2 answers:
Kazeer [188]3 years ago
7 0
So there are 4 possibilities:
Dice 1: 1 2 3 4
Dice2: 4 3 2 1

notka56 [123]3 years ago
4 0
5 or lower: (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,2), (4,1)

There are 9 valid rolls out of 36 total possible rolls = 9/36 = 1/4
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2 years ago
Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
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Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

6 0
3 years ago
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