Answer:
To answer this question we would need the Molecular empirical formula that relates the reactant of N2 to the final product of CH3NH2. Then it would be easily solved by using stoichiometric ratios. Basically it is done similar to unit conversion problems.
Answer:
Molar mass of Al2O3 = 101.961276 g/mol
This compound is also known as Aluminium Oxide.
Convert grams Al2O3 to moles or moles Al2O3 to grams
Molecular weight calculation:
26.981538*2 + 15.9994*3
Percent composition by element
Element Symbol Atomic Mass # of Atoms Mass Percent
Aluminium Al 26.981538 2 52.925%
Oxygen O 15.9994 3 47.075%
Explanation:
Percent composition by element
Element Symbol Mass Percent
Aluminium Al 52.925%
Oxygen O 47.075%
The average atomic mass of Sn is 118.71 g/mol
the percentage of heaviest Sn is 5.80%
the given mass of Sn is 82g
The total moles of Sn will be = mass / atomic mass = 82/118.71=0.691
Total atoms of Sn in 82g =
the percentage of heaviest Sn is 5.80%
So the total atoms of = 5.80% X
Total atoms of = atoms
the mass of will be =
Answer:
Number of produced moles of carbondioxide is 0.113 mol.
Explanation:
Excess of sulphuric acid is present.And the sodium carbonate is completely consumed.
Molar mass of sodium carbonate = 105.99g/mol
Given mass of sodium carbonate =12 g/mol
one mole of sodium carbonate produce one mole of carbondioxide.
0.113 mole of sodium carbonate produce 0.113 mole of carbondioxide.
Therefore, 0.113 mol of carbondioxide produced in flask 7.
The answer is C. The others are either a compound or an element