HELP ASAP!!!!!!!!!!
1 answer:
You might be interested in
Answer: Concentration of in the equilibrium mixture is 0.31 M
Explanation:
Equilibrium concentration of = 0.729 M
The given balanced equilibrium reaction is,
Initial conc. x 0 0
At eqm. conc. (x-2y) M (y) M (3y) M
The expression for equilibrium constant for this reaction will be:
3y = 0.729 M
y = 0.243 M
Now put all the given values in this expression, we get :
concentration of in the equilibrium mixture =
Thus concentration of in the equilibrium mixture is 0.31 M