Answer:
2360J
Explanation:
Given parameters:
Mass of aluminum = 25g
Melting point = 658°C
Latent heat of melting = 94.4j/g
Unknown:
Amount of heat require for melting = ?
Solution:
The amount of heat required for this melting will be the product of the mass of the aluminum and the latent heat of melting;
H = m L
m is the mass
L is the latent heat of melting
Insert the parameters and solve;
H = 25 x 94.4 = 2360J
Moving Water, The Wind, and Absorbant Soil
Answer:
4.96 mol/dm³
Explanation:
From the question,
Mass of NaCl that dissolved in 0.5L of water = 500-346.8 = 153.2 g.
Therefore, 145.2(1/0.5)g of NaCl will dissolve in 1 L of water
mass of NaCl that will dissolve in 1 L of water = 290.4 g/dm³
Molar mass of NaCl = 58.5 g/mol.
Solubility is the amount of substance in mol that will dissolve in 1 L or 1 dm³ Solution.
solubility in (mol/dm³) = solubility in (g/dm³)/molar mass.
solubility in (mol/dm³) = 290.4/58.5
solubility in (mol/dm³) = 4.96 mol/dm³