Answer:
E ’= E / 8
therefore the correct answer is A
Explanation:
Let's calculate the electric field in an insulating sphere with a radius r <R, let's use Gauus's law, with a spherical Gaussian surface
Фi = ∫ E. dA = /ε₀
E (4πr²) = q_{int} / ε₀
density is
ρ = q_{int} / V
q_{int} = ρ V = ρ 4/3 π r³
we substitute
E (4π r²) = ρ 4/3 π r³ /ε₀
E = 1 /3ε₀ ρ r
let's change the density by
ρ = Q / V = Q / (4/3 π R³)
E = 1 / 4πε₀ Q r / R³
if we now distribute the same charge on a sphere of radius R' = 2R
E ’= 1 / 4pieo Q r / (2R)³
E ’= 1 / 4ft Qr / R³ ⅛
E ’= E / 8
therefore the correct answer is A
The function rule that would describe the relationship between the time, t, and the distance, d, a wildebeest travels when running at full speed is (d=rt). This is distance traveled is equal to the rate times the time traveled. Therefore, the answer would be d=66t for r=66/s.
I will discuss what is a gravitational force since no figures are attached or given. An objects weight is dependent upon its location in the universe
because they exhibit gravitational waves. For example, the earth is a massive
planet. Because of its massiveness, it exhibits a strong gravitational force
within it. In turn, the objects near the earth will be attracted to it and
thereby feels a much stronger gravity on earth. That is why bodies of water,
despite its liquid features, stick to the earth. The heavier the body is, the
stronger its gravitational pull. Another example is the Milky Way Galaxy, there is a
gravitational pull because it is to other galaxies. Also, other galaxies are
heavier than the earth and therefore, it is attracted to the Milky Way galaxy
because of its gravitational pull.