The power of the lamp would be calculated with the equation of ohm laws. P = U x I = 122V x 0.1A = 12.2W
The total work done by the electric field on the charge is given by the scalar product between the electric force acting on the charge and the displacement of the charge:

where the force is F=qE, d=0.556 and

. Using the value of q and E given by the problem, we find
If one of two interacting charges is doubled, the force between the charges will double.
Explanation:
The force between two charges is given by Coulomb's law

K=constant= 9 x 10⁹ N m²/C²
q1= charge on first particle
q2= charge on second particle
r= distance between the two charges
Now if the first charge is doubled,
we get 
F'= 2 F
Thus the force gets doubled.
Answer:
Explanation: In DC circuit, the current will flow for a short time, which is required to charge the capacitor. Once you switch it on, it spikes and the gradually decreases to almost zero (0) as the capacitor becomes fully charged.
In an AC circuit, the circuit acts as if the current is flowing throw the plates whereas is not actually flowing. The circuit acts like the AC is flowing through the capacitor.
Answer:
length
Explanation:
SI unit of volume = m^3
SI unit of area = m^2
volume unit / Area unit = m^3 / m^2
i.e, unit of length