Plz help me im really confused. The questions are in the second pic and the vehicles are in the first the fetures are in the las
t 3 the check mars are just to see which data for that vehicle is safer. The check marks are just to see which data is safer for that car.
1 answer:
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Answer:
ma = 48.48kg
Explanation:
To find the mass of the astronaut, you first calculate the mass of the chair by using the information about the period of oscillation of the empty chair and the spring constant. You use the following formula:
(1)
mc: mass of the chair
k: spring constant = 600N/m
T: period of oscillation of the chair = 0.9s
You solve the equation (1) for mc, and then you replace the values of the other parameters:
(2)
Next, you calculate the mass of the chair and astronaut by using the information about the period of the chair when the astronaut is sitting on the chair:
T': period of chair when the astronaut is sitting = 2.0s
M: mass of the astronaut plus mass of the chair = ?
(3)
Finally, the mass of the astronaut is the difference between M and mc (results from (2) and (3)) :
The mass of the astronaut is 48.48 kg
(a)
Let's take the initial direction (before the collision) of the cue ball has positive x-direction.
Along the y-direction, the total initial momentum is zero:
Therefore, since the total momentum must be conserved, it must be zero also after the collision. So we write:
where
m is the mass of each ball
is the velocity of the cue ball after the collision
is the velocity of the second ball after the collision
is the angle of the cue ball with the x-axis
is the angle of the second ball
Solving for , we find the angle between the direction of motion of the second ball and the original direction of motion:
(b) 6.69 m/s
To find the original speed of the cue ball, we analyze the situation along the horizontal direction.
First, we calculate the total momentum along the x-direction after the collision, which is:
The initial total momentum along the x-direction as
where
m is the mass of the cue ball
is the initial velocity of the cue ball
The momentum along this direction must be conserved, so we can equate the two expressions and find the value of u: