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mel-nik [20]
3 years ago
7

An oil slick is expanding as a circle. The radius of the circle is currently 2.5 inches and is increasing at a rate of 6.5 inche

s per hour. Express the area of the circle, A as a function of h, the number of hours elapsed.
Mathematics
1 answer:
aleksandrvk [35]3 years ago
7 0

Answer:

A = \pi r^2

So we can express the radius in terms of the hours elapsed like this:

r = 2.5 + 6.5 h

And the reason of this is because each hour the radius increase 6.5 inches, and if we replace in the formula of area we got:

A = \pi (2.5 +6.5 h)^2

And this function would represent the area of the circle as function of the hours elapsed, h\geq 0

Step-by-step explanation:

For this case we know the radius of a circle given r = 2.5 in and we also know the incresing rate for the radius:

\frac{dr}{dt}= 6.5 \frac{inches}{\hour}

And we want to express the are of the circle A as a function of h = the number of hours elapsed.

We know that the area of a circle is given by:

A = \pi r^2

So we can express the radius in terms of the hours elapsed like this:

r = 2.5 + 6.5 h

And the reason of this is because each hour the radius increase 6.5 inches, and if we replace in the formula of area we got:

A = \pi (2.5 +6.5 h)^2

And this function would represent the area of the circle as function of the hours elapsed, h\geq 0

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