Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
Answer:
-2x + 8
Step-by-step explanation:
(2x - 6) is subtracted from (7 - 5).
First term that into an equation.
Because our first term is being subtracted from our second one, our equation is written as:
(7 - 5) - (2x - 6).
Simplify the first term by subtracting:
7 - 5 = 2
Now simplify the second term by multiplying 2x - 6 by -1 to get them out of the parenthesis. We do this because there is a negative sign in front of it.
-1 (2x - 6)
-2x + 6
Now our equation is:
2 - 2x + 6
Combine like terms:
2 + 6 = 8
So -2x + 8
(2x - 6) subtracted from (7 - 5) is -2x+8
Answer:
5
Step-by-step explanation:
Answer:
He could buy 2 brackets
Step-by-step explanation:
42.50- 29= 13.50 and if you buy two that's nine (9.00) + plus tax does not go over budget (shirt included)
