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2 years ago

Mona bought a camera for Rs 1300 and sold it at 15 percent at what price should she sell it tell?

Mathematics

2 answers:

Lynna [10]2 years ago

8 0

Answer:

Rs.1495

Step-by-step explanation:

15%=1300*15/100

=Rs.195

Selling price=1300+195

=Rs.1495

Ann [662]2 years ago

6 0

Answer:

Rs 195

Step-by-step explanation:

Working out 15% of 1300

Write 15% as

15/100

Since, finding the fraction of a number is same as multiplying the fraction with the number, we have

15/100 of 1300 =

15/100 × 1300 = 195

Therefore, the answer is 195

If you use a calculator, simply enter 15÷100×1300 which will give you 195 as the answer.

15% of 1300 is 195

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Answer:

The test statistic for the appropriate test is $\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$ .

Step-by-step explanation:

The experiment conducted here is to determine whether there is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. north and south.

The hypothesis to test this can be defined as follows:

H₀: There is no difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. p₁ = p₂.

Hₐ: There is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. p₁ ≠ p₂.

The two-proportion z-test would be used to perform the test.

A sample of n = 40 starfishes are selected from both the ocean areas.

It provided that of the 40 starfish from the north, 6 were found to be over 8 inches in length and of the 40 starfish from the south, 11 were found to be over 8 inches in length.

Compute the sample proportion of starfish from north that were over 8 inches in length as follows:

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Compute the sample proportion of starfish from south that were over 8 inches in length as follows:

$\hat p_{s}=\frac{11}{40}=0.275$

The test statistic is:

$z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}$

Compute the combined proportion P as follows:

$P=\frac{X_{n}+X_{s}}{n_{n}+n_{s}}=\frac{6+11}{40+40}=0.2125$

Compute the test statistic value as follows:

$z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}$

$=\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$

Thus, the test statistic for the appropriate test is $\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$ .

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2 years ago

Mona bought a camera for Rs 1300 and sold it at 15 percent at what price should she sell it tell?​

Mona bought a camera for Rs 1300 and sold it at 15 percent at what price should she sell it tell?