Find the missing value. sin x = .65

1 answer:

mote1985 [20]2 years ago

7 0

Remark
This is just a calculator problem. Look around on your calculator for the sin button

Above it you will find something like sin-1. that will give you the answer.

Here's how you do it with most calculators.
2nd F
Sin-1(
0.65
=
You should get 40.54 <<<<<<<< answer

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castortr0y [4]

Answer:

D is the correct representation.

$\frac{\frac{4x^2 + 2x}{x^{2}+x-2} }{ \frac{8x^2 +4x}{3x^2 +10x+8} }$ = ${\frac{(3x+4)}{2(x-1)}$

Step-by-step explanation:

Here, the given equation is:

$\frac{\frac{4x^2 + 2x}{x^{2}+x-2} }{ \frac{8x^2 +4x}{3x^2 +10x+8} }$

here, numerator = ${\frac{4x^2 + 2x}{x^{2}+x-2} }$

and denominator = $\frac{8x^2 +4x}{3x^2 +10x+8}$

Solving numerator and denominator separately, we get

NUMERATOR:

${\frac{4x^2 + 2x}{x^{2}+x-2} } \implies\frac{2x(2x +1)}{x^{2} + 2x-x-2 } \\\implies\frac{2x(2x +1)}{(x+2)(x-1) }$

Denominator:

$\frac{8x^2 +4x}{3x^2 +10x+8} = \frac{4x(2x+1)}{3x^2 +6x+ 4x+8}\\ \implies \frac{4x(2x+1)}{3x(x+2)+ 4(x+2)} = \frac{4x(2x+1)}{(3x+4)(x+2)}$

Hence, the transformed fraction is:

$\frac{\frac{2x(2x +1)}{(x+2)(x-1) }}{\frac{4x(2x+1)}{(3x+4)(x+2)}} = {\frac{2x(2x +1)}{(x+2)(x-1) }} \times{\frac{(3x+4)(x+2)}{4x(2x+1)}$

or, implied fraction is ${\frac{(3x+4)}{2(x-1)}$

Hence, D is the correct representation.

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Answer:

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Step-by-step explanation:

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Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 2−x+1 intersect are the so

11Alexandr11 [23.1K]

You probably mean the equations are y = 4 - x and y = 2x -1. Else with given equations, the solution is not possible. The steps of the solution are listed below:

Part A)
The solution to the equation 4 - x = 2x + 1 are the points where both the equations have same value for a given value of x. This means, if a points (x,y) lies on both the lines it will be the solution of the given equations. Since that point lies on both the lines, both lines will cross that point. Crossing that point can be seen as intersection of two lines at that point.
Therefore, x-coordinates of the points where the graphs of equations y = 4 - x and y = 2x + 1 intersect are the solutions of the equation 4 - x = 2x + 1

Part B)
The table is attached in the images below. As seen from the table, both lines have same value of y for x =1. So x=1 is the solution to the equation 4 - x = 2x + 1

Part C)
In order to solve the equation 4 - x = 2x + 1 , we plot the individual lines y = 4 - x and y = 2x + 1 on the graph. The point of intersection of two lines will be the solution to the equation. The graph of lines is attached below.