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Artemon [7]
3 years ago
13

(3.rº – 7x + 2) - (2x² – 4x + 5)

Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

choice C: x2 -3x -3

Step-by-step explanation:

(3x^2-7x+2)-(2x^2-4x+5)

becomes

3x^2-7x+2 -2x^2+4x-5

adding

3x^2-2x^2 -7x+4x +2-5

which is

x^2 -3x -3

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What is the GCF of 8 and 24?
Marysya12 [62]

The factors of 8 are 1, 2, 4, and 8.


The factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24.


The largest factor that is in both these lists is 8, therefore, the greatest common factor os 8 and 24 is 8.


Hope this helped! (:

3 0
3 years ago
Read 2 more answers
What is the value of y?<br> B<br> 60°<br> 12<br> 12<br> ro<br> 60°<br> А<br> 12 to 60
Umnica [9.8K]

answer 60°

solve:180°-(60°+60°)

180°-120°

60°##

4 0
3 years ago
How many cubes with side lengths of cm does it take to fill the prism?
Sophie [7]
The answer is Stan twiceushisnsskkemr
5 0
2 years ago
Kara’s car used 1/16 gallons of gas to drive 1/8 of a mile at this rate how many miles can Kara’s car drive using one gallon of
marissa [1.9K]
Answer is 2 miles
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8 0
2 years ago
Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)
zubka84 [21]
\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } &#10;

This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

\frac{ \sqrt{-49}}{7-2i-4-9i}

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result: 

\frac{ \sqrt{-49} }{3-11i}

Now, the \sqrt{-49} must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to \sqrt{49}  \sqrt{-1}
This means that we get the result 7i for the numerator.

\frac{7i}{3-11i}

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: x^2 - y^2 =(x+y)(x-y)
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

\frac{7i (3+11i)}{(3-11i)(3+11i)}

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how (3-11i)(3+11i)= 3^2 -(11i)^2 therefore, we can finally write:

\frac{7i(3+11i)}{3^2 - (11i)^2 }

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product 7i(3+11i) = 21i+77i^2.
You should know from your classes that i^2 = -1, thefore the numerator simplifies to -77+21i
You can do it as a curious thing, but simplifying yields the result:
\frac{-77+21i}{130}
7 0
3 years ago
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