Answer:
Step-by-step explanation:
39). y =
x + 3
40). m =
y -
= m( x -
)
(- 7, 5)
( - 12, 4)
m = ( 4 - 5 ) / ( - 12 + 7) = 1/5
y - 5 = (1/5)(x + 7) ⇒ y =
x + 6.4
Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC